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cestrela7 [59]
4 years ago
10

The energy from our sun is produced by _____.

Physics
2 answers:
lesya [120]4 years ago
5 0
█ Answer <span>█

</span><span>The energy from our sun is produced by fusion of hydrogen. 

Choice D is the answer. 

</span><span>Hope that helps! ★ If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia 
</span>
dedylja [7]4 years ago
3 0

Answer: D. fusion of hydrogen

Explanation:

Nuclear fusion is a process which involves the conversion of two small nuclei to form a heavy nuclei along with release of energy.

Nuclear fission is a process which involves the conversion of a heavier nuclei into two or more small and stable nuclei along with the release of energy.

The reactions which takes place in sun follows a series of equations:

_1^1\textrm{H}+_1^1\textrm{H}\rightarrow 1^2\textrm{H}+_{+1}^0\textrm{e}+\text{energy}\\\\_1^2\textrm{H}+_1^1\textrm{H}\rightarrow 2^3\textrm{He}+\text{energy}\\\\_2^3\textrm{He}+_1^1\textrm{H}\rightarrow _2^4\textrm{He}+_{+1}^0\textrm{e}+\text{energy}

Overall reaction for the above series of reactions is given by:

4_1^1\textrm{H}\rightarrow _2^4\textrm{He}+2_{+1}^0\textrm{e}+\text{energy}

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The radiation is ultra voilet or Gamma radiation , because their wave length is very short i e 1..0 to 2.5 (angstrom)Ao.
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What happens if :<br> . The test charge is not tiny.
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The magnitude of the test charge must be small enough so that it does not disturb the issuance of the charges whose electric field we wish to measure otherwise the metric field will be different from the actual field.

<h3>How does test charge affect electric field?</h3>

As the quantity of authority on the test charge (q) is increased, the force exerted on it is improved by the same factor. Thus, the ratio of force per charge (F / q) stays the same.

Adjusting the amount of charge on the test charge will not change the electric field force.

<h3>What is a test charge used for?</h3>

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Give a example of scalar quantity
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speed, volume, mass, temperature and power

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3 years ago
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A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long
Degger [83]

Answer:

(A). The work done by friction in crossing the patch is -637.98 J.

(B). The speed of skier is 10.57 m/s.

Explanation:

Given that,

Mass of skier = 62 kg

Speed = 6.5 m/s

Length = 3.50 m

Coefficient kinetic friction = 0.30

Height = 2.5 m

(A) we need to calculate the work done by friction in crossing the patch

Using formula of work done

W=-\mu mg\times l

Put the value into the formula

W=-0.30\times62\times9.8\times3.50

W=-637.98\ J

The work done by friction in crossing the patch is -637.98 J.

(B) we need to calculate the speed of skier

Using conservation of energy

K.E_{i}+U_{i}-W_{friction}=K.E_{f}+U_{f}

\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2+U_{f}

Final potential energy is zero

So, \dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}v_{1}^2+gh-\mu gl

Put the value into the formula

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}\times6.5^2+9.8\times2.5+0.30\times9.8\times3.50

v_{2}=\sqrt{2\times55.915}

v_{2}=10.57\ m/s

The speed of skier is 10.57 m/s.

Hence,  (A).The work done by friction in crossing the patch is -637.98 J.

(B).The speed of skier is 10.57 m/s.

6 0
3 years ago
PLEASE HELP !!!
emmainna [20.7K]

Answer and Explanation:

The answer is <u>D) Alpha and Gamma</u>

Gamma radiation does not cause transmutations.

A <u>transmutation</u> is the <u>conversion of an atom of one element to an atom of another. This generally occurs through nuclear reacting.</u>

There are three main types of radiation: alpha, beta, and gamma. Both beta and alpha decay cause changes to the mass and atomic numbers. This results in a transmutation. Gamma radiation, however, does not.

Gamma radiation is the result of a gamma ray. In essence, the nucleus emits a high-energy proton. This is very penetrating and can only be stopped by aluminum, lead, soil, water, and concrete. This type of radiation does not change the element and, therefore, does not cause a transmutation.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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