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const2013 [10]
3 years ago
7

The following statements are about the laminar boundary layer over a flat plate. For each statement, answer whether the statemen

t is true or false.
1. At a given x-location, if the Reynolds number were to increase, the boundary layer thickness would also increase.
A. True B. False
2. As outer flow velocity increases, so does the boundary layer thickness.
A. True B. False
3. As the fluid viscosity increases, so does the boundary layer thickness.
A. True B. False
4. As the fluid density increases, so does the boundary layer thickness.
A. True B. False
5. The boundary layer equations are approximations of the Navier-Stokes equation.
A. True B. False
6. The curve representing boundary layer thickness as function of x is a streamline.
A. True B. False
7. The boundary layer approximation bridges the gap between the Euler equation and the Navier-Stokes equation.
A. True B. False
Engineering
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

1. B. False

2.  B. False

3. A. True

4. B. False

5. A. True

6. A. True

7. A. True

Explanation:

1. B. False

The relation of Reynolds' number, Reₓ to boundary layer thickness δ at a point x is given by the relation

\delta = \dfrac{x \times C}{\sqrt{Re_x} }

That is the boundary layer thickness is inversely proportional to the square root of the Reynolds' number so that if the Reynolds' number were to increase, the boundary layer thickness would decrease

Therefore, the correct option is B. False

2.  B. False

From the relation

Re_x = \dfrac{U_o \times x}{v}

As the outer flow velocity increases, the boundary layer thickness diminishes

3. A. True

As the viscous force is increased the boundary layer thickness increases

4. B. False

Boundary layer thickness is inversely proportional to velocity

5. A. True

The boundary layer model developed by Ludwig Prandtl is a special case of the Navier-Stokes equation

6. A. True

Given a definite boundary layer thickness, the curve representing the boundary layer thickness is a streamline

7. A. True

The boundary layer approximation by Prandtl Euler bridges the gap between the Euler (slip boundary conditions) and Navier-Stokes (no slip boundary conditions) equations.

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A Weave lane is a single lane used by drivers to enter and exit a freeway.

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6 0
2 years ago
What is the step in which you are testing your hypothesis ​
jonny [76]

Answer:

Step 1: State your null and alternate hypothesis. ...

Step 2: Collect data. ...

Step 3: Perform a statistical test. ...

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8 0
3 years ago
1. Sewage-treatment plant, a large concrete tank initially contains 440,000 liters liquid and 10,000 kg fine suspended solids. T
Elenna [48]

Answer:

Concentration = 10.33 kg/m³

Explanation:

We are given;

Mass of solids; 10,000 kg

Volume; V = 440,000 L = 440 m³

Rate at which water is pumped out = 40,000 liter/h

Thus, at the end of 5 hours we amount of water that has been replaced with fresh water is = 40,000 liter/h x 5 hours = 200,000 L = 200 m³

Now, since the tank is perfectly mixed, therefore we can calculate a ratio of fresh water to sewage water as;

200m³/440m³ = 5/11

Thus, the amount left will be calculated by multiplying that ratio by the amount of solids;

Thus,

Amount left; = 10000 x (5/11) = 4545 kg

The concentration would be calculated by:

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Thus,

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8 0
3 years ago
When you apply for your driver license, you consent to take a ____ test when asked to do so by a law enforcement officer. memory
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Answer:

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4 0
2 years ago
Water flows in a tube that has a diameter of D= 0.1 m. Determine the Reynolds number if the average velocity is 10 diameters per
Cloud [144]

Answer:

a) Re_{D} = 111896.745, b) Re_{D} = 1.119\times 10^{-7}

Explanation:

a) The Reynolds number for the water flowing in a circular tube is:

Re_{D} = \frac{\rho\cdot v\cdot D}{\mu}

Let assume that density and dynamic viscosity at 25 °C are 997\,\frac{kg}{m^{3}} 0.891\times 10^{-3}\,\frac{kg}{m\cdot s}, respectively. Then:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (1\,\frac{m}{s} )\cdot (0.1\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

Re_{D} = 111896.745

b) The result is:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (10^{-6}\,\frac{m}{s} )\cdot (10^{-7}\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

Re_{D} = 1.119\times 10^{-7}

6 0
4 years ago
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