I would honestly select every one of the given options. Gor a company evaluating this new material it would be very valuable to hit each of these factors.
Complete Question:
A metal plate of 400 mm in length, 200mm in width and 30 mm in depth is to be machined by orthogonal cutting using a tool of width 5mm and a depth of cut of 0.5 mm. Estimate the minimum time required to reduce the depth of the plate by 20 mm if the tool moves at 400 mm per second.
Answer:
26 mins 40 secs
Explanation:
Reduction in depth, Δd = 20 mm
Depth of cut, 
Number of passes necessary for this reduction, 
n = 20/0.5
n = 40 passes
Tool width, w = 5 mm
Width of metal plate, W = 200 mm
For a reduction in the depth per pass, tool will travel W/w = 200/5 = 40 times
Speed of tool, v = 100 mm/s

minimum time required to reduce the depth of the plate by 20 mm:
number of passes * Time/pass
n * Time/pass
40 * 40
1600 = 26 mins 40 secs
Answer:
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Explanation:
Answer:
P = 4.745 kips
Explanation:
Given
ΔL = 0.01 in
E = 29000 KSI
D = 1/2 in
LAB = LAC = L = 12 in
We get the area as follows
A = π*D²/4 = π*(1/2 in)²/4 = (π/16) in²
Then we use the formula
ΔL = P*L/(A*E)
For AB:
ΔL(AB) = PAB*L/(A*E) = PAB*12 in/((π/16) in²*29*10⁶ PSI)
⇒ ΔL(AB) = (2.107*10⁻⁶ in/lbf)*PAB
For AC:
ΔL(AC) = PAC*L/(A*E) = PAC*12 in/((π/16) in²*29*10⁶ PSI)
⇒ ΔL(AC) = (2.107*10⁻⁶ in/lbf)*PAC
Now, we use the condition
ΔL = ΔL(AB)ₓ + ΔL(AC)ₓ = ΔL(AB)*Cos 30° + ΔL(AC)*Cos 30° = 0.01 in
⇒ ΔL = (2.107*10⁻⁶ in/lbf)*PAB*Cos 30°+(2.107*10⁻⁶ in/lbf)*PAC*Cos 30°= 0.01 in
Knowing that PAB*Cos 30°+PAC*Cos 30° = P
we have
(2.107*10⁻⁶ in/lbf)*P = 0.01 in
⇒ P = 4745.11 lb = 4.745 kips
The pic shown can help to understand the question.
Answer:
Re=100,000⇒Q=275.25 
Re=500,000⇒Q=1,757.77
Re=1,000,000⇒Q=3060.36 
Explanation:
Given:
For air
=25°C ,V=8 m/s
For surface
=179°C
L=2.75 m ,b=3 m
We know that for flat plate
⇒Laminar flow
⇒Turbulent flow
<u> Take Re=100,000:</u>
So this is case of laminar flow

From standard air property table at 25°C
Pr= is 0.71 ,K=26.24
So 
Nu=187.32 (
)
187.32=
⇒h=1.78
heat transfer rate =h
=275.25 
<u> Take Re=500,000:</u>
So this is case of turbulent flow


Nu=1196.18 ⇒h=11.14 
heat transfer rate =h
=11.14(179-25)
= 1,757.77
<u> Take Re=1,000,000:</u>
So this is case of turbulent flow


Nu=2082.6 ⇒h=19.87 
heat transfer rate =h
=19.87(179-25)
= 3060.36 