Answer:
The new concentration is 0.125 M.
Explanation:
Given data:
Initial volume V₁ = 125.0 mL
Initial molarity M₁ = 0.150 M
New volume V₂ = 25 mL +125 mL = 150 mL
New concentration M₂ = ?
Solution:
M₁V₁ = M₂V₂
0.150 M × 125 mL = M₂ × 150 mL
M₂ = 0.150 M × 125 mL / 150mL
M₂ = 18.75 M.mL/150 mL
M₂ = 0.125 M
The new concentration is 0.125 M.
The masses of solute in the 2 solutions can be different but result in the same concentration, this is best explained with examples.
Say solution A contained 10g of solute and had a volume of 100dm^3
If solution B contained 5g of solute and had a volume of 50dm^3 this would make the concentrations of A and B identical.
Answer:
Helium can be liquefied, but its condensation temperature is the lowest among all the known substances. Helium has many unique properties: low boiling point, low density, low solubility, high thermal conductivity and inertness, so it is use for any application which can explioit these properties.
Explanation:
Sorry if its to long (I could maybe shorten it if needed)
Answer:
F, N O, C, B
Explanation:
Ionization on the periodic table, goes from left to right, so in order to decrease in ionization, you go right to left.
Therefore leading to (F)luorine, (N)itrogen, (O)oxygen, (C)arbon, and (B)oron
Q methane = Q water
Q = mcΔt
mass water = V x ρ = 1 L x 1 kg/L = 1 kg
298 K to 373K = 25 °C to 100 °C
c water = 75.2 J/mol K = 4.2 J / g °C = 4200 J/kg °C
Q water = 1 x 4200 x (100 - 25)
Q water = 315000 J
Q methane = Q water = 315000 J = 315 KJ
n (mol) methane = ΔH/Q = 890.4 / 315 = 2.83
PV = nRT
V = nRT/P
V = 2.83 x 0.082 x 298/1
V = 69.15 L