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Wewaii [24]
3 years ago
7

During the apollo missions,an astronaut took a golf ball to the moon. He placed it on the moon’s surface and hit the ball with a

golf club. Which property of the golf ball was different on the moon than on earth?
A.) density
B.) mass
C.) volume
D.) weight
Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
3 0

Answer:

b.)

Explanation:

Because you would have a different weight on the moon because of it's low gravity

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What is the pH when the hydrogen ion concentration is 1 x 10-3 M?
Fynjy0 [20]

Answer:

e. 3

Explanation:

In order to solve this problem we need to keep in mind the definition of pH:

  • pH = -log[H⁺]

As stated by the problem, the hydrogen ion concentration, [H⁺], is 1x10⁻³ M.

As all required information is available, we now can <u>calculate the pH</u>:

  • pH = -log(1x10⁻³ M)
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The correct option is thus e.

6 0
2 years ago
When Z-4,5-dimethyloct-4-ene is treated with hydrogen chloride, HCl, the result is:________.
Vika [28.1K]

Answer:

The  correct option is  c

Explanation:

The chemical equation for the reaction of  Z-4,5-dimethyloct-4-ene and HCl is shown on the first uploaded image

Now looking at the product we see that there are two who has four different groups attached to them this carbon are known as chiral carbons hence the product formed is a pair of diastereomers

6 0
3 years ago
What are alternative periodic tables
aksik [14]
Tabulations of chemical elements differing in their organization from the traditional seen periodic system
5 0
3 years ago
Nombra cada uno de los siguientes hidrocarburos de acuerdo a las reglas de la IUPAC
myrzilka [38]

Answer:

i) ciclobutano

ii) 3-etil-4-metil ciclopenteno

Explanation:

Toda la idea de la nomenclatura IUPAC es permitir que la estructura de la sustancia se derive de su nombre y viceversa.

La nomenclatura IUPAC es un sistema universalmente aceptado para nombrar compuestos químicos.

los nombres de los compuestos enumerados son;

i) ciclobutano

ii) 3-etil-4-metil ciclopenteno

3 0
2 years ago
The percent composition by mass of magnesium MgBr2 (gram formula mass= 184 grams/mole) is equal to...
k0ka [10]
The percent composition by mass of an element is determined by dividing the molar mass of the element by the molar mass of the compound. In this case, the molar mass of magnesium is 24. Hence the answer to this problem is A. 24/184 x 100
4 0
3 years ago
Read 2 more answers
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