<span>The only scenario that
will allow you to reach an equilibrium mixture involving these chemicals is to
place NH3 into a sealed vessel. This reaction requires pressures between 2100,
3600 psi, and temperatures between 300 and 550 degree Celsius. With this given
temperature and pressure, the ammonia naturally decomposes into nitrogen and
hydrogen gas at the same rate. When this happen, the concentrations of these
chemicals become constant and the system is said to be at equilibrium.</span>
37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2
<span>4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms.
I think this is the answer.</span>
I believe the correct response is the first option.
Answer:
las rondas sirven para ayudar con problemas matematicos asi como cilindros
6.4 x 10^-7 = [CO]^2[O2]/ [CO2}^2 = ( 2.0 x 10^-3)^2 ( 1.0 x 10^-3)/ [CO2]^2 =
<span>=4.0 x 10^-9 / [CO2]^2 </span>
<span>[CO]= sq.rt ( 4.0 x 10^-9)/ 6.4 x 10^-7=7.9 x 10^-2 M </span>
<span>2.6 x 10^-3 = [I]^2 / [I2] = [I]^2 / 0.95 </span>
<span>[I]= sq.rt ( 2.6 x 10^-3 x 0.95)=5.0 x 10^-2 M </span>
<span>Ksp = [Ba2+][CO32-] = ( 1.1 x 10^-4)^2=1.2 x 10^-8</span>
