How many oxygen atoms are there in 1665 grams of iron(II) phosphate? Please explain how you found your answer.
1 answer:
Answer:
About 2.24 × 10²⁵ oxygen atoms
Explanation:
We want to determine the amount of oxygen atoms in 1665 grams of iron (II) phosphate (Fe₃(PO₄)₂).
To do so, we can convert from grams to moles of iron (II) phosphate, moles of iron (II) phosphate to moles of oxygen, and finally to atoms of oxygen.
Find the molar mass of iron (II) phosphate:
From the chemical formula, we can see that for each molecule of iron (II) phosphate, there are eight oxygen atoms. In other words, each mole of iron (II) phosphate has eight moles of oxygen atoms.
Finally, each mole of a substance contains 6.02 × 10²³ amount of that substances.
With the initial amount, multiply:
In conclusion, there are about 2.24 × 10²⁵ oxygen atoms in 1665 grams of iron (II) phosphate.
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Answer:
Enthalpy of formation = -947.68KJ/mol
Explanation:
Enthalpy of formation is the heat change when one mole of a substance is formed from its element in its standard states and in standard conditions of temperature and pressure. it may be positive or negative, if positive, it is an endothermic reaction where the heat content of the product is greater than that of the reactants, and if negative, it is exothermic reaction - where the heat content of the reactants is greater than the products. the enthalpy of formation is measured in KiloJoule/Moles (KJ/Mole).
From the value of the enthalpy of formation of NaHCO3, it shows that the reaction is exothermic, that is the formation of NaHCO3 from its constituents elements. As such, the heat content of the reactants is greater than the products.
The step by step explanation is shown in the attachment.
Above question is incomplete. Complete question is attached below
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Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.
In present case, reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is least reactive.
On other hand, reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is most reactive.
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Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.
In present case, reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is least reactive.
On other hand, reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is most reactive.