All categories

2 years ago

How many oxygen atoms are there in 1665 grams of iron(II) phosphate? Please explain how you found your answer.

Chemistry

1 answer:

elena-14-01-66 [18.8K]2 years ago

8 0

Answer:

About 2.24 × 10²⁵ oxygen atoms

Explanation:

We want to determine the amount of oxygen atoms in 1665 grams of iron (II) phosphate (Fe₃(PO₄)₂).

To do so, we can convert from grams to moles of iron (II) phosphate, moles of iron (II) phosphate to moles of oxygen, and finally to atoms of oxygen.

Find the molar mass of iron (II) phosphate:

$\displaystyle \begin{aligned} \text{Molecular Weight} & = 3(55.85 + 2(30.97) + 8(16.00))\text{ g/mol} \\ \\ & = 357.49\text{ g/mol}\end{aligned}$

From the chemical formula, we can see that for each molecule of iron (II) phosphate, there are eight oxygen atoms. In other words, each mole of iron (II) phosphate has eight moles of oxygen atoms.

Finally, each mole of a substance contains 6.02 × 10²³ amount of that substances.

With the initial amount, multiply:

$\displaystyle \begin{aligned} 1665 \text{ g Fe$_3$(PO$_4$)$_2$} \cdot \frac{1 \text{ mol Fe$_3$(PO$_4$)$_2$}}{357.49 \text{ g Fe$_3$(PO$_4$)$_2$}}& \cdot \frac{8\text{ mol O}}{1 \text{ mol Fe$_3$(PO$_4$)$_2$}} \\ \\ &\cdot \frac{6.02\times 10^{23} \text{ atom O}}{1 \text{ mol O}} \\ \\ &=2.24\times 10^{25} \text{ atom O}\end{aligned}$

In conclusion, there are about 2.24 × 10²⁵ oxygen atoms in 1665 grams of iron (II) phosphate.

You might be interested in

Use the periodic table to identify the chemical symbol or name for each element below.

Tom [10]

Answer:yes

Explanation:yeaa

4 0

3 years ago

Read 2 more answers

What is the genetic makeup of both parents ?

Effectus [21]

Answer:

A, T, C y G, son las "letras" del código del ADN; representan los compuestos químicos adenina (A), timina (T), citosina (C) y guanina (G), respectivamente, que constituyen las bases de nucleótidos del ADN. ...El código genético es el conjunto de reglas que define cómo se traduce una secuencia de nucleótidos en el ARNm a una secuencia de aminoácidos en una proteína

7 0

3 years ago

A megamole of titanium contains __________ moles of titanium.

Gala2k [10]

Answer is: 1 megamole is equal to 1000000 (one million) mole or 10⁶<span> moles</span>.
The SI base unit for amount of substance is the mole. The SI prefix "mega" represents a factor of 10⁶, or in exponential notation, 1E6.
<span>The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 12 grams of carbon C-12.</span>

8 0

3 years ago

Read 2 more answers

Some SbCl5 is allowed to dissociate into SbCl3 and Cl2 at 521 K. At equilibrium, [SbCl5] = 0.195 M, and [SbCl3] = [Cl2] = 6.98×1

Brilliant_brown [7]

Answer:

a) The equilibrium will shift in the right direction.

b) The new equilibrium concentrations after reestablishment of the equilibrium :

$[SbCl_5]=(0.370-x) M=(0.370-0.0233) M=0.3467 M$

$[SbCl_3]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M$

$[Cl_2]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M$

Explanation:

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

a) Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On increase in amount of reactant

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

If the reactant is increased, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where more product formation is taking place. As the number of moles of $SbCl_5$ is increasing .So, the equilibrium will shift in the right direction.