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navik [9.2K]
3 years ago
11

5-A baseball is hit with a velocity of 15 m/s at an angle of 40° in the horizontal direction. What are the horizontal and vertic

al vector components of the velocity vector?
A•Horizontal =9.64 m/s
Vertical=11.49 m/s

B•Horizontal=11.49 m/s
Vertical=9.64 m/s

C•Horizontal=25 m/s
Vertical=25 m/s

D•Horizontal =75 m/s
Vertical =75 m/s

Number 6 is in the picture. TIA

Physics
1 answer:
borishaifa [10]3 years ago
5 0

<u>Answer</u>

B•Horizontal=11.49 m/s  

Vertical=9.64 m/s

Using the concept of a trigonometric ratios,

sin θ  = y/hypotenuse

where y is the vertical component.

sin 40 = y/15

y = 15 × sin 40

  = 9.64 m/s

vertical component = 9.64 m/s

cos θ  = x/hypotenuse

where x is the horizontal component

cos 40 = x/15

x = 15 × cos 15

    =11.49

Horizontal component = 11.49 m/s

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