5-A baseball is hit with a velocity of 15 m/s at an angle of 40° in the horizontal direction. What are the horizontal and vertic
al vector components of the velocity vector?
A•Horizontal =9.64 m/s
Vertical=11.49 m/s
B•Horizontal=11.49 m/s
Vertical=9.64 m/s
C•Horizontal=25 m/s
Vertical=25 m/s
D•Horizontal =75 m/s
Vertical =75 m/s
Number 6 is in the picture. TIA
1 answer:
<u>Answer</u>
B•Horizontal=11.49 m/s
Vertical=9.64 m/s
Using the concept of a trigonometric ratios,
sin θ = y/hypotenuse
where y is the vertical component.
sin 40 = y/15
y = 15 × sin 40
= 9.64 m/s
vertical component = 9.64 m/s
cos θ = x/hypotenuse
where x is the horizontal component
cos 40 = x/15
x = 15 × cos 15
=11.49
Horizontal component = 11.49 m/s
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