I, i’m pretty sure sorry if it’s wrong
Answer:
![0.5083\ \mu m](https://tex.z-dn.net/?f=0.5083%5C%20%5Cmu%20m)
Explanation:
= Actual wavelength = ![0.61\ \mu m](https://tex.z-dn.net/?f=0.61%5C%20%5Cmu%20m)
= Relative permittivity = 1.44
The observed wavelength in the glass is given by
![\lambda=\dfrac{\lambda_0}{\sqrt{\varepsilon_r}}\\\Rightarrow \lambda=\dfrac{0.61}{\sqrt{1.44}}\\\Rightarrow \lambda=0.5083\ \mu m](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B%5Clambda_0%7D%7B%5Csqrt%7B%5Cvarepsilon_r%7D%7D%5C%5C%5CRightarrow%20%5Clambda%3D%5Cdfrac%7B0.61%7D%7B%5Csqrt%7B1.44%7D%7D%5C%5C%5CRightarrow%20%5Clambda%3D0.5083%5C%20%5Cmu%20m)
The wavelength lies in the range of green light.
Hence, the observed color of light is ![0.5083\ \mu m](https://tex.z-dn.net/?f=0.5083%5C%20%5Cmu%20m)
<span>b)Determine your horisontal distance from window (ans. 1.5 m)
c)Calc the speed of ball as you catch it (ans: 8.2m/s)
I dont get what 42 m below the horizontal is, can someone give me direction on how to do this?
</span>
Answer:
Q = 200800 Joules.
Explanation:
Given the following data;
Mass = 4kg
Initial temperature = 30.0°C
Final temperature = 90.0°C
Specific heat capacity of glass = 837 J/kg°C
To find the quantity of heat absorbed;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 90 - 30
dt = 60°C
Substituting the values into the equation, we have;
Q = 200800 Joules.
Therefore, the amount of heat absorbed is 200800 Joules.
Answer:
We need about 8769 meters of wire to produce a 2.6 kilogauss magnetic field.
Explanation:
Recall the formula for the magnetic field produced by a solenoid of length L. N turns, and running a current I:
![B=\mu_0\,\frac{N}{L} \,I](https://tex.z-dn.net/?f=B%3D%5Cmu_0%5C%2C%5Cfrac%7BN%7D%7BL%7D%20%5C%2CI)
So, in our case, where B = 2.6 KG = 0.26 Tesla; I is 3 amperes, and L = 0.57 m, we can find what is the number of turns needed;
![B=\mu_0\,\frac{N}{L} \,I\\0.26=4\,\pi\,10^{-7}\frac{N}{0.57} \,3\\N=\frac{0.26*0.57\,10^7}{12\,\pi} \\N=39311.27](https://tex.z-dn.net/?f=B%3D%5Cmu_0%5C%2C%5Cfrac%7BN%7D%7BL%7D%20%5C%2CI%5C%5C0.26%3D4%5C%2C%5Cpi%5C%2C10%5E%7B-7%7D%5Cfrac%7BN%7D%7B0.57%7D%20%5C%2C3%5C%5CN%3D%5Cfrac%7B0.26%2A0.57%5C%2C10%5E7%7D%7B12%5C%2C%5Cpi%7D%20%5C%5CN%3D39311.27)
Therefore we need about 39312 turns of wire. Considering that each turn must have a length of
, where D is the diameter of the plastic cylindrical tube, then the total length of the wire must be:
![Length=39312\,(\pi\,D)=39312\,(\pi\,0.071)\approx 8768.66\,\,m](https://tex.z-dn.net/?f=Length%3D39312%5C%2C%28%5Cpi%5C%2CD%29%3D39312%5C%2C%28%5Cpi%5C%2C0.071%29%5Capprox%208768.66%5C%2C%5C%2Cm)
We can round it to about 8769 meters.