Which of the following is not true regarding atmospheric pressure

A 1200 kg aircraft going 30 m/s collides with a 2000 kg aircraft that is parked and they stick together after the collision and

Leno4ka [110]

Answer:

83.055 m

Explanation:

According to the given scenario, the calculation of skid distance is shown below:-

$S = \frac{1}{2} \times (u + v) \times t$

Where

u = 11.3

v = 0

t = 14.7

Now placing these values to the above formula,

So,

$S = \frac{1}{2} \times (11.3 + 0) \times 14.7$

= 83.055 m

Therefore for computing the skid distance we simply applied the above formula i.e by considering the all items given in the question

4 0

2 years ago

A 5.00X10^5 kg rocket is accelerating straight up. Its engines produce 1.250X10^7 N of thrust, and air resistance is 4.50X10^6 N

katrin [286]

<span>6.20 m/s^2 The rocket is being accelerated towards the earth by gravity which has a value of 9.8 m/s^2. Given the total mass of the rocket, the gravitational drag will be 9.8 m/s^2 * 5.00 x 10^5 kg = 4.9 x 10^6 kg m/s^2 = 4.9 x 10^6 N Add in the atmospheric drag and you get 4.90 x 10^6 N + 4.50 x 10^6 N = 9.4 x 10^6 N Now subtract that total drag from the thrust available. 1.250 x 10^7 - 9.4 x 10^6 = 12.50 x 10^6 - 9.4 x 10^6 = 3.10 x 10^6 N So we have an effective thrust of 3.10 x 10^6 N working against a mass of 5.00 x 10^5 kg. We also have N which is (kg m)/s^2 and kg. The unit we wish to end up with is m/s^2 so that indicates we need to divide the thrust by the mass. So 3.10 x 10^6 (kg m)/s^2 / 5.00 x 10^5 kg = 0.62 x 10^1 m/s^2 = 6.2 m/s^2 Since we have only 3 significant figures in our data, the answer is 6.20 m/s^2</span>

8 0

2 years ago

if the charge of each two particles is doubled and the seperation between them is also doubled. the force between the two partic

jok3333 [9.3K]

Explanation is in this link

https://doubtnut.app/physics-question/when-the-distance-between-two-charged-particles-is-doubled-the-force-between-them-becomes-422318076

4 0

3 years ago

A laser beam enters a 16.5 cm thick glass window at an angle of 58.0° from the normal. The index of refraction of the glass is 1

ivann1987 [24]

Answer:

using Snells law

Oi = angle of incidence = 58.0°

ni = index of refraction of air = 1.0003

nr = index of refraction of glass = 1.47

c = speed of light in vacuum = 3 x 10^8 m/s

Or = angle of refraction = ?

ni(sinOi) = nR (sinOr)

ni( sinOi)/ nR = sinOr

arcsin(ni(sin0i))/nR = Or

arcsin( 1.0003(sin58.0)) / 1.47

Or = 35.25°

Explanation:

5 0

2 years ago

Read 2 more answers

Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous plan

lianna [129]

Answer: E. 450 K

Explanation:

It is given that the temperature of the gaseous planet is linearly related with height of the atmosphere. we can write this in the mathematical equation:

y = m x +c

where y is the temperature values, x is height, m is the slope and c is the y-intercept. we have been given two sets of value in the image, using which we can find the value of slope in y-intercept.

at x = 18.40 km, y = 147.54 K

⇒147.54 = 18.40 m + c

⇒c = 147.54 - 18.40 m ..(1)

at x =78.11 km, y = 567.00 K

⇒567.00 =78.11 m + c ..(2)

Put equation 1 in 2 and solve:

⇒567.00 =78.11 m + 147.54 - 18.40 m

⇒419.46 = 59.71 m

⇒ m =419.46 ÷59.71 = 7.025 K/km

c = 147.54 - 18.40 × 7.025 = 18.28 K

At height, x = 61.5 km the approximate temperature is :

y = 7.025 K/km × 61.5 km + 18.28 K = 450.3 K

Thus, the approximate temperature at altitude 61.5 km is 450 K.

8 0

3 years ago