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Reil [10]
3 years ago
6

Find the value of the underlined number 380,671 -

Mathematics
1 answer:
netineya [11]3 years ago
5 0
Hope this helps

3 hundred thousands
8 ten thousands
0 thousands
, digit grouping
6 hundreds
7 tens
1 units
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Solve the triangle. Round your answers to the nearest tenth. Law of sines 6 A. M∠C=34 m ∠ C = 34 , b=25 b = 25 , c=16 c = 16 B.
PolarNik [594]

Answer:

A  = 43.0^o

B = 55.0^o

BC = 20.0

Step-by-step explanation:

I will solve this question with the attached triangle

From the attachment, we have:

\angle C =82^o

AB = 29

AC = 24

Required

Solve the triangle

First, we calculate \angle B using sine law:

\frac{AC}{\sin(B)} = \frac{AB}{\sin(C)}

This gives:

\frac{24}{\sin(B)} = \frac{29}{\sin(82^o)}

\frac{24}{\sin(B)} = \frac{29}{0.9903}

Cross multiply

\sin(B) * 29 = 24 * 0.9903

\sin(B) * 29 = 23.7672

Divide both sides by 29

\sin(B) = 0.8196

Take arcsin of both sides

B = \sin^{-1}(0.8196)

B = 55.0^o

Next, calculate \angle A using:

A + B + C = 180^o --- angles in a triangle

A + 55^o + 82^o = 180^o

Collect like terms

A  = 180^o-55.0^o - 82^o

A  = 43.0^o

Next, calculate BC using sine laws

\frac{BC}{\sin(A)} = \frac{AB}{\sin(C)}

This gives:

\frac{BC}{\sin(43.0)} = \frac{29}{\sin(82)}

\frac{BC}{0.6820} = \frac{29}{0.9903}

Make BC the subject

BC = \frac{29*0.6820}{0.9903}

BC = 20.0

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2 years ago
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iragen [17]

Answer:

Step-by-step explanation:

7/12-2/5

We will find the LCM of it to make the denominators same.

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Now to make denominators same

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2/5×12/12

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Now using these like values

35/60-24/60

= 11/60

The fraction is already in lowest terms

Must click thanks and mark brainliest

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3 years ago
Harry collects data from a random sample of seventh-graders. Out of 25 respondents, 10 ride the bus home. Of the 150 seventh-gra
alekssr [168]

10/25=x/150

x=60

so 60 students

WELCOME MOA!!!

#SOOBIN

#YEONJUN

#TAEHYUN

#BEOMGYU

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^_________^<( ̄︶ ̄)>

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3 years ago
Read 2 more answers
-2x+4=10 <br> 3/4x =2<br> Plz help ill give brainly
Archy [21]

Answer:

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Step-by-step explanation:

please mark me brainliest

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3 years ago
Which step can be used to prove that triangle EFG is also a right triangle?
Darya [45]
EFG is the same as angle KLM. therefore, it is the reflection of the angle KLM
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