A sheet of gold foil has a volume of 0.750 cm3. If the foil measures 50.0cm by 10.0cm, what is the thickness of the foil?

Physics

1 answer:

vlada-n [284]3 years ago

6 0

To calculate the thickness of foil, we use formula of volume as

$V= l w t$

Here, l is the length of the foil, w is the width of the foil and t is the thickness of the foil.

Given, $V = 0.750 \ cm^3$ , $l = 50 cm$ and $w = 10 \ cm$ .

Substituting theses values in above equation, we get

$0.750 \ cm^3 = 50 cm \times 10 \ cm \times t \\\\ t = 0.0015 cm$

Thus, the thickness of the foil is 0.0015 cm.

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