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leonid [27]
3 years ago
11

A sheet of gold foil has a volume of 0.750 cm3. If the foil measures 50.0cm by 10.0cm, what is the thickness of the foil?

Physics
1 answer:
vlada-n [284]3 years ago
6 0

To calculate the thickness of foil, we use formula of volume as

V= l w t

Here, l is the length of the foil, w is the width of the foil and t is the thickness of the foil.

Given,  V = 0.750 \ cm^3, l = 50 cm and w = 10 \ cm.

Substituting theses values in above equation, we get

0.750 \ cm^3 = 50 cm \times 10 \ cm \times t \\\\ t =  0.0015 cm

Thus, the thickness of the foil is 0.0015 cm.

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To find the answer, we need to know about the orbital velocity of a satellite.

<h3>What's the expression of orbital velocity of a satellite?</h3>
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<h3>What's the orbital velocity of a satellite orbiting earth with a radius 3.57 times the earth radius?</h3>
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