1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
charle [14.2K]
3 years ago
12

Calculate the kinetic energy of a 100.0-kg meteor approaching the Earth at a speed of 10.0 km/s. Remember that 1 km = 1000 m.

Physics
2 answers:
Alex17521 [72]3 years ago
8 0
Kinetic Energy = (1/2) (mass) (speed squared)

Mass = 100 kg
Speed = 10 km/s = 10,000 m/s
Speed squared = 100,000,000 m²/s²

1/2 (M)(V²) = 1/2 (100) (100,000,000) = 5,000,000,000 joules  (5 x 10⁹ J)

That's  5 billion joules.

That's the amount of energy a 100-watt light bulb uses in  579 days.
olchik [2.2K]3 years ago
5 0
KE=1/2 x mass x speed^2
Substitute:

KE=1/2 x 100 x 10000^2
5000000000J of KE
So either <u>5 gigajoules</u>
Or <u>5x10^9J</u>
You might be interested in
1. Applied research observational evidence 2. Basic research the experimental factor that changes in response to a change in the
lesya [120]

Answer:

This question is about matching each definition with its correct term. Please find the term matched with their appropriate definition below.

Explanation:

1. Empirical evidence: An empirical evidence is an observational evidence i.e an evidence gathered by observation or use of senses.

2. Dependent variable: Dependent variable is an experimental factor that changes in response to a change in the independent variable. In other words, it is dependent on the independent variable.

3. Applied research: Applied research is a type of research oriented at solving a present problem or need. It encompasses the production of products that can be sold for profit.

4. Hypothesis: A hypothesis in an experiment is a proposed explanation for a scientific problem that itself can be tested by experimentation. A hypothesis aims at providing a testable explanation to an observed problem.

5. Control: A control is a quantity in an experiment that remains unchanged or constant. It is kept the same by the experimenter for all groups in the experiment in order not to influence the outcome.

6. Basic research: Basic research is the research that expands knowledge in a particular area. It is the kind of research that aims at filling a knowledge void or satiating curiosity.

7. Independent variable: The independent variable is the experimental factor that is changed or manipulated deliberately by the scientist.

8 0
3 years ago
Using the image provided, which moon phase is next?
ella [17]

Answer:

Waning Crescent

5 0
2 years ago
Read 2 more answers
Which term describes the transfer of thermal energy from one object to another because of a difference in temperature? 1.energy
gregori [183]
The answer is 3.heat
6 0
3 years ago
Read the paragraph below from the section "An Object At Rest Has Potential Energy
ch4aika [34]
I think it’s d because it talks about a spring with is common like the spring in a pen
8 0
3 years ago
A practical rule is that a radioactive nuclide is essentially gone after 10 half-lives. What percentage of the original radioact
ArbitrLikvidat [17]

Answer:

  • 0.09 % of the original radioactive nucllde its left after 10 half-lives
  • It will take 241,100 years for 10 half-lives of plutonium-239 to pass.

Explanation:

The equation for radioactive decay its:

N ( t) \ = \ N_0 \ e^{ \ -  \frac{t}{\tau}},

where N(t) its quantity of material at time t, N_0 its the initial quantity of material and \tau its the mean lifetime of the radioactive element.

The half-life t_{\frac{1}{2}} its the time at which the quantity of material its the half of the initial value, so, we can find:

N (t_{\frac{1}{2} }) \ = \ N_0 \ e^{ \ -  \frac{t_{\frac{1}{2}}}{\tau}} \ = \frac{N_0}{2}

so:

\ N_0 \ e^{ \ -  \frac{t_{\frac{1}{2}}}{\tau}} \ = \frac{N_0}{2}

e^{ \ -  \frac{t_{\frac{1}{2}}}{\tau}} \ = \frac{1}{2}

-  \frac{t_{\frac{1}{2}}}{\tau}} \ = - \ ln( 2 )

t_{\frac{1}{2}}\ = \tau ln( 2 )

So, after 10 half-lives, we got:

N ( 10 \  t_{\frac{1}{2}}) \ = \ N_0 \ e^{ \ -  \frac{10 \  t_{\frac{1}{2}}}{\tau}}

N ( 10 \  t_{\frac{1}{2}}) \ = \ N_0 \ e^{ \ -  \frac{10 \  \tau \ ln( 2 ) }{\tau}}

N ( 10 \  t_{\frac{1}{2}}) \ = \ N_0 \ e^{ \ -  10 \  \ ln( 2 ) }

N ( 10 \  t_{\frac{1}{2}}) \ = \ N_0 \ * \ 9.76 * 10^{-4}

So, we got that a 0.09 % of the original radioactive nucllde its left.

Putonioum-239 has a half-life of 24,110 years. So, 10 half-life will take to pass

10 \ * \ 24,110 \ years \ = \ 241,100 \ years

It will take 241,100 years for 10 half-lives of plutonium-239 to pass.

7 0
3 years ago
Read 2 more answers
Other questions:
  • Difference between static and kinetic friction in physics
    13·1 answer
  • What’s the answer to this problem ? with work pls !!
    9·1 answer
  • How many electrons are depicted in the electron dot diagram of an electrically neutral nitrogen atom? A. two B. six C. eight D.
    10·2 answers
  • 26. The speed of light in a certain medium is
    10·1 answer
  • lood flows through a section of a horizontal artery that is partially blocked by a deposit along the artery wall. As a hemoglobi
    12·1 answer
  • An Alaskan rescue plane traveling 45 m/sdrops a package of emergency rations froma height of 145 m to a stranded party of reese
    14·1 answer
  • Six members of a synchronized swim team wear earplugs to protect themselves against water pressure at depths, but they can still
    5·1 answer
  • Protons are______<br> charged particles.
    8·2 answers
  • A motorcycle passes over the top of a hill that has a radius of curvature of 100 m. The mass of the motorcycle plus rider is 300
    14·1 answer
  • Match to the correct answers
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!