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NikAS [45]
3 years ago
11

A 35 kg box rests on the back of a truck. The coefficient of static friction bet?005 (part 1 of 2)A 35 kg box rests on the back

of a truck. Thecoefficient of static friction between box andtruck bed is 0.202.The acceleration of gravity is 9.8 m/s2 .When the truck accelerates forward, whatforce accelerates the box?006 (part 2 of 2)
What maximum acceleration can the truck
have before the box slides?
Answer in units of m/s2.
Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

Answer with Explanation:

We are given that

Mass of box=35 kg

Coefficient of static friction between box and truck bed=0.202

Acceleration due to gravity=9.8 m/s^2

a.We have to find the force by which the box accelerates forward.

Force by which box accelerates=\mu mg=0.202\times 9.8\times 35

Force by which box accelerates=62.286 N

b.We have to find the maximum acceleration can the truck have before the box slides.

Force =friction force

ma=\mu mg

a=\mu g=9.8\times 0.202=1.9796 m/s^2

Hence, the truck can have maximum acceleration before the box slide=1.9796 m/s^2

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