According to the gravitational force law, force existing between two objects is proportional to the mass of the two objects and inversely proportional to the square of the distance between them. When masses are doubled each. Then the force increases 16 times.
Answer:
For the air:
Final Velocity 160.77m/s
Final Elevation 1,317.43m
the Internal, Kinetic, and Potential Energy changes will be equal.
Explanation:
In principle we know the following:
- <u>Internal Energy:</u> is defined as the energy contained within a system (in terms of thermodynamics). It only accounts for any energy changes due to the internal system (thus any outside forces/changes are not accounted for). In S.I. is defined as where is the mass (kg), is a specific constant-volume (kJ/kg°C) and is the Temperature change in °C.
- <u>Kinetic Energy:</u> denotes the work done on an object (of given mass ) so that the object at rest, can accelerate to reach a final velocity. In S.I. is defined as where is the velocity of the object in (m/s).
- <u>Potential Energy:</u> denotes the energy occupied by an object (of given mass ) due to its position with respect to another object. In S.I. is defined as , where is the gravity constant equal to and is the elevation (meters).
<em>Note: The Internal energy is unaffected by the Kinetic and Potential Energies.</em>
<u>Given Information:</u>
- Temperature Change 0°C → 18°C ( thus °C )
- Object velocity we shall call it and , for initial and final, respectively. Here we also know that
- Object elevation we shall call it and , for initial and final, respectively. Here we also know that
∴<em> We are trying to find and of the air where , and are equal.</em>
Lets look at the change in Energy for each.
<u>Step 1: Change in Kinetic Energy=Change in Internal Energy</u>
Here we recall that and mass is the same everywhere. Thus we have:
Eqn(1)
<u>Step 2: Change in Potential Energy=Change in Internal Energy</u>
Here we recall that and mass is the same everywhere. Thus we have:
Eqn(2).
Finally by plugging the known values in Eqns (1) and (2) we obtain:
Thus we can conclude that for the air final velocity and final elevation the internal, kinetic, and potential energy changes will be equal.
Answer:
Here you go..
hope it helps..!
Explanation:
So since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force, so as the mass of either object increases, the force of gravitational attraction between them also increases.
The speed of the second mass after it has moved ℎ=2.47 meters will be 1.09 m/s approximately
<h3>
What are we to consider in equilibrium ?</h3>
Whenever the friction in the pulley is negligible, the two blocks will accelerate at the same magnitude. Also, the tension at both sides will be the same.
Given that a large mass m1=5.75 kg and is attached to a smaller mass m2=3.53 kg by a string and the mass of the pulley and string are negligible compared to the other two masses. Mass 1 is started with an initial downward speed of 2.13 m/s.
The acceleration at which they will both move will be;
a = ( - ) / ( + )
a = (5.75 - 3.53) / (5.75 + 3.53)
a = 2.22 / 9.28
a = 0.24 m/s²
Let us assume that the second mass starts from rest, and the distance covered is the h = 2.47 m
We can use third equation of motion to calculate the speed of mass 2 after it has moved ℎ=2.47 meters.
v² = u² + 2as
since u =0
v² = 2 × 0.24 × 2.47
v² = 1.1856
v = √1.19
v = 1.0888 m/s
Therefore, the speed of mass 2 after it has moved ℎ=2.47 meters will be 1.09 m/s approximately
Learn more about Equilibrium here: brainly.com/question/517289
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