Altered means to change something.
Well, 0.1 is actually less than 0.7, but I understand what you're asking.
The coefficient of friction describes the relationship between two surfaces
that are sliding by each other. The higher the coefficient of friction is, the
'rougher' the meeting is, and the harder it is for one to slide over the other.
A skate blade against ice has a very low coefficient of friction. Sandpaper
against blue jeans has a high coefficient of friction.
A higher coefficient of friction means that when one thing is sliding over
the other one, friction robs more energy from the motion. It's harder to
push one thing over the other one, and when you let go, the moving one
slows down and stops sooner.
Air resistance is actually an example of friction. It prevents falling things
from falling as fast as they would if there were no air. The coefficient of
friction when something moves through air is pretty low. If the same
object were trying to move through molasses or honey, the coefficient
of friction would be greater.
Friction robs energy, and turns it into heat. So, especially in machinery with
moving parts, we want to make the coefficient of friction between the moving parts
as small as possible. That's what the OIL in a car's engine is for.
First, we resolve the northeast displacement into its north and east components. The angle from the positive x-axis of a northeast displacement is 45 degrees. Thus:
North = 8.46sin(45) = 5.98 m
East = 8.46cos(45) = 5.98 m
North displacement = 5.98 - 3.6 = 2.38 m
West displacement = 15.6 - 5.98 = 9.62
Magnitude = √(2.38² + 9.62²)
Magnitude = 9.91 m
Direction:
tan∅ = 2.38 / 9.62
∅ = 13.9° north from east
<h2>
Formula which describes v in terms of t is 
</h2>
Explanation:
A train travels the distance between the points A and B, which is 600 km
Distance between A and B = 600 km
Speed of train = v
Time taken by train = t
We know that
Distance traveled = Speed of travel x Time taken
600 = v x t

Formula which describes v in terms of t is 
Answer:
charge, q = ± 1.1 mC
Given:
Capacitance, 
Voltage, V = 110 V
Solution:
The charge on the capacitor plates can be calculated by using the definition of capacitance as :
q ∝ V
where
q = charge
V = potential difference or Voltage
Therefore,
q = CV
Now, charge, q :
q = 
Therefore, the charge on the positive plate is:
q = + 1.1 mC
the charge on the negative plate is:
q = - 1.1 mC