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Kay [80]
1 year ago
11

a tire has a tread pattern with a crevice every 4.00 cm. each crevice makes a single vibration as the tire moves. what is the fr

equency (in hz) of these vibrations if the car moves at 24.2 m/s?
Physics
1 answer:
koban [17]1 year ago
5 0

the frequency (in hz) of these vibrations if the car moves at 24.2 m/s is 605 HZ .

Calculation :

frequency = \frac{number of contacts}{second}

frequency = \frac{24.2 m/s}{1}*100cm*\frac{1}{4cm}

= 605 HZ

Frequency describes the number of waves passing through a particular location in a particular time. So if the wave takes 1/2 second to travel, the frequency is 2 per second. If it takes 1/100th of an hour, the frequency is 100 per hour.

Frequency is the number of occurrences of a repeating event per unit time. ... sometimes called time-frequency for clarity,

Learn more about frequency here : brainly.com/question/254161

#SPJ4

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what does it mean if the coefficient of friction is greater? for example,a coefficient of friction of 0.1 compared to 0.7
Sergeu [11.5K]
Well, 0.1 is actually less than 0.7, but I understand what you're asking.

The coefficient of friction describes the relationship between two surfaces
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A higher coefficient of friction means that when one thing is sliding over
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Air resistance is actually an example of friction.  It prevents falling things
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of friction would be greater.

Friction robs energy, and turns it into heat.  So, especially in machinery with
moving parts, we want to make the coefficient of friction between the moving parts
as small as possible.  That's what the OIL in a car's engine is for.
3 0
3 years ago
Read 2 more answers
Your dog is running around the grass in your backyard. He undergoes successive displacements, 3.60 m south, 8.46 m northeast, an
Eduardwww [97]
First, we resolve the northeast displacement into its north and east components. The angle from the positive x-axis of a northeast displacement is 45 degrees. Thus:
North = 8.46sin(45) = 5.98 m
East = 8.46cos(45) = 5.98 m

North displacement = 5.98 - 3.6 = 2.38 m
West displacement = 15.6 - 5.98 = 9.62

Magnitude = √(2.38² + 9.62²)
Magnitude = 9.91 m

Direction:
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3 0
3 years ago
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Moving with a speed of v km/hour, a train travels the distance between the points A and B, which is 600 km, in t hours. Find the
NARA [144]
<h2>Formula which describes v in terms of t is v=\frac{600}{t}km/hr</h2>

Explanation:

A train travels the distance between the points A and B, which is 600 km

Distance between A and B = 600 km

Speed of train = v

Time taken by train = t

We know that

              Distance traveled = Speed of travel x Time taken

              600 = v x t

               v=\frac{600}{t}km/hr

Formula which describes v in terms of t is v=\frac{600}{t}km/hr

3 0
3 years ago
What charge appears on each plate of a 10.0 μF parallel plate capacitor, when it is charged to 110 V?
elena-14-01-66 [18.8K]

Answer:

charge, q = ± 1.1 mC

Given:

Capacitance, C = 10.0\micro F = 10.0\times 10^{- 6} F

Voltage, V = 110 V

Solution:

The charge on the capacitor plates can be calculated by using the definition of capacitance as :

q ∝ V

where

q = charge

V = potential difference or Voltage

Therefore,

q = CV

Now, charge, q :

q = 10.0\times 10^{- 6}\times 110 = 1100\micro C = 1.1 mC

Therefore, the charge on the positive plate is:

q = + 1.1 mC

the charge on the negative plate is:

q = - 1.1 mC

8 0
2 years ago
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