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Anestetic [448]
3 years ago
14

To study Earth’s interior, geologists often rely on indirect methods, such as evidence from fossils. true or false

Chemistry
2 answers:
Sphinxa [80]3 years ago
8 0

Answer: FALSE

Explanation:To study Earth’s interior, geologists often rely on indirect methods, such as evidence from fossils.

andreyandreev [35.5K]3 years ago
4 0

Answer:

the answer is false, the person that said true is incorect.

Explanation:

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Pt5 science......<br><br> Select correct answer ♡ !
arlik [135]

Answer: what answer? wahhhhhhhat

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4 0
3 years ago
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What is the molecular formula of eggs?
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C37H70NaO8P is the molecular formula for an egg
5 0
3 years ago
You have used 2.4×102 L of distilled water for a dialysis patient. How many gallons of water is that?
Alinara [238K]

Answer:

63.36gallons

Explanation:

Given:

Volume of water used for dialysis = 2.4 x 10²L

Solution:

We are to convert from liters to gallons.

The conversion factor is shown below:

                1L = 0.264gallons

To convert to litre:

       since 1L = 0.264gallons

             2.4 x 10²L = (2.4 x 10² x 0.264)gallons; 63.36gallons

3 0
3 years ago
What is the total pressure exerted by a mixture of 48.0 grams of CH4 and 56.0 grams of
Oksi-84 [34.3K]

The pressure of the gas is obtained as 48 atm.

<h3>What is the total pressure?</h3>

Now we know that;

Number of moles of CH4 = 48.0 grams /16 g/mol = 3 moles

Number of moles of H2 =  56.0 grams/2 g/mol = 28 moles

Total number of moles present = 3 moles + 28 moles = 31 moles

Using;

PV =nRT

P = total pressure

V = total volume

n = total number of moles

R = gas constant

T = temperature

P = nRT/V

P = 31 * 0.082 * 286/15

P = 48 atm

Learn more about pressure of a gas:brainly.com/question/18124975

#SPJ1

4 0
1 year ago
How many grams of F2 gas are there in a 5.00-L cylinder at 4.00 × 10^3 mm Hg and 23°C?
GuDViN [60]

Answer:

41.17g

Explanation:

We are given the following parameters for Flourine gas(F2).

Volume = 5.00L

Pressure = 4.00× 10³mmHG

Temperature =23°c

The formula we would be applying is Ideal gas law

PV = nRT

Step 1

We find the number of moles of Flourine gas present.

T = 23°C

Converting to Kelvin

= °C + 273k

= 23°C + 273k

= 296k

V = Volume = 5.00L

R = 0.08206L.atm/mol.K

P = Pressure (in atm)

In the question, the pressure is given as 4.00 × 10³mmHg

Converting to atm(atmosphere)

1 mmHg = 0.00131579atm

4.00 × 10³ =

Cross Multiply

4.00 × 10³ × 0.00131579atm

= 5.263159 atm

The formula for number of moles =

n = PV/RT

n = 5.263159 atm × 5.00L/0.08206L.atm/mol.K × 296K

n = 1.0834112811moles

Step 2

We calculate the mass of Flourine gas

The molar mass of Flourine gas =

F2 = 19 × 2

= 38 g/mol

Mass of Flourine gas = Molar mass of Flourine gas × No of moles

Mass = 38g/mol × 1.0834112811moles

41.169628682grams

Approximately = 41.17 grams.

3 0
3 years ago
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