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Gennadij [26K]
3 years ago
12

Protons size and mass ?

Chemistry
1 answer:
Cloud [144]3 years ago
5 0
A proton's mass is 1.6726231*10-27 kg, and the size of its radius is around 0.84×10−15 to 0.87×10−15 m.
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NaBr + CaF2 → NaF + CaBr2 What coefficients are needed to balance the chemical equation? A) 1,1,1,1 B) 1,2,1,2 C) 1,2,2,1 D) 2,1
elena-s [515]
D.
2NaBr + CaF2 --> 2NaF + CaBr2 gives you:

2Na                        2Na
2Br                         2F
1Ca                         1Ca
2F                           2Br

This is balanced.
7 0
2 years ago
Read 2 more answers
The ph of a 0.0100 m solution of the sodium salt of a weak acid is 11.00. what is the ka of the acid?
Vitek1552 [10]
The answer is Ka = 1.00x10^-10.
Solution:
When given the pH value of the solution equal to 11, we can compute for pOH as
     pOH = 14 - pH = 14 - 11.00 = 3.00
We solve for the concentration of OH- using the equation
     [OH-] = 10^-pOH = 10^-3 = x

Considering the sodium salt NaA in water, we have the equation
     NaA → Na+ + A- 
hence, [A-] = 0.0100 M

Since HA is a weak acid, then A- must be the conjugate base and we can set up an ICE table for the reaction
                             A- + H2O ⇌ HA + OH-
     Initial             0.0100            0       0
     Change        -x                    +x     +x
     Equilibrium    0.0100-x         x       x

We can now calculate the Kb for A-:
     Kb = [HA][OH-] / [A-] 
           = x<span>²</span> / 0.0100-x
Approximating that x is negligible compared to 0.0100 simplifies the equation to
     Kb = (10^-3)² / 0.0100 = 0.000100 = 1.00x10^-4

We can finally calculate the Ka for HA from the Kb, since we know that Kw = Ka*Kb = 1.0 x 10^-14:
     Ka = Kw / Kb 
           = 1.00x10^-14 / 1.00x10^-4
           = 1.00x10^-10
7 0
3 years ago
Elements in what family are all gases?
Alina [70]

Answer:

Noble gases.

Good Luck & Have a good day!

(.❛ ᴗ ❛.)

6 0
3 years ago
Please help me with this homework
KengaRu [80]

Answer:

The answer is C density.

8 0
2 years ago
If you are given 12M HCL how would you make a 6M of 100mL? SHow the math and explain the process
AlladinOne [14]

dilution

V₁M₁=V₂M₂

V₁.12 = 100.6

V₁=50 ml

Add water 50 ml to 50 ml 12 M

7 0
2 years ago
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