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Gennadij [26K]
3 years ago
12

Protons size and mass ?

Chemistry
1 answer:
Cloud [144]3 years ago
5 0
A proton's mass is 1.6726231*10-27 kg, and the size of its radius is around 0.84×10−15 to 0.87×10−15 m.
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What is friction force ?
Degger [83]
What is the resistance to motion
5 0
3 years ago
The mass of an unidentified metal sphere is 133 grams. Students determine the
Rainbow [258]

Given the data from the question, the identity of the unknown metal having a of mass 133 g is Cobalt

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

<h3>How to determine the density </h3>
  • Mass = 133 g
  • Volume of water = 25 mL
  • Volume of water + metal = 40 mL
  • Vol of metal = 40 – 25 = 15 mL
  • Density =?

Density = mass / volume

Density = 133 / 15

Density = 8.86 g/mL

Comparing the density of the unknown metal (i.e 8.86 g/mL) with those given in the chart in the question above, we can conclude that the unknown metal is Cobalt

Learn more about density:

brainly.com/question/952755

4 0
2 years ago
What factors affect the geometry of a molecule?
natali 33 [55]

The factors that affect geometry of a molecule are

> The number of bonding electron pairs around the central atom.

> The number of pairs of non-bonding ("lone pair") electrons around the central atom.

4 0
3 years ago
Identify the acid, base, conjugate acid and conjugate base in the following reactions:
Leni [432]

Answer:

a. NH₃ : base

CH₃COOH (acetic acid) : acid

NH₄⁺ : conjugate acid

CH₃COO⁻ : conjugate base

b. HClO₄ (perchloric acid) : acid

NH₃ : base

ClO₄⁻ : conjugate base

NH₄⁺ : conjugate acid

Hope this helps.

4 0
3 years ago
The following data was collected when a reaction was performed experimentally in the laboratory.
REY [17]

Answer:

The answer to your question is 3 moles of AlCl₃

Explanation:

Process

1.- Write and balance the equation

                  Al(NO₃)₃ + 3NaCl   ⇒   3NaNO₃  +  AlCl₃

2.- Determine the limiting reactant

Theoretical proportion     1 mol Al(NO₃)₃ :  3 moles of NaCl                  

Experimental proportion   4 moles Al(NO₃)₃ : 9 moles NaCl

From these values, we determine that the limiting reactant is NaCl because the number of moles increases three times and the number of moles of Al(NO₃)₃  increases four times.

3.- Determine the amount of AlCl₃ using proportions

                       3 moles of NaCl --------------- 1 mol of AlCl₃

                       9 moles of NaCl ----------------  x

                       x = (9 x 1) / 3

                       x = 9 /3

                       x = 3 moles

                     

5 0
3 years ago
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