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Marina CMI [18]
3 years ago
6

La masa de una olla es de 300g y contiene 90% de aluminio. Hallar el número de moles de aluminio de la olla. P.A.(Al= 27)

Chemistry
1 answer:
Neko [114]3 years ago
6 0

Explanation:

The mass of a pot is 300g and contains 90% aluminum. Find the number of moles of aluminum in the pot. P.A. (Al = 27)

The mass of aluminum present in the pot is:

300 g * 90/100\\=270 g

Hence, in the given pot 270g Al is present.

Number of moles of Al=\frac{given mass ofAl}{its molar mass}

The gram atomic mass of Al -27 g/mol

Given the mass of Al is 270 g

Substitute these values in the above formula:

Number of moles of Al=\frac{given mass ofAl}{its molar mass}\\=\frac{270 g}{27 g} \\=10.0 mol

Answer is 10.0 mol of Al is present.

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Why is it important for a measurement system to have an international standard ?
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What are the three energy's .
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How many grams of CaOH2 are in this solution? The molar mass of CaOH2 is 58.093 g/mol. (0.0787 mol CaOH2) (58.093 g/mol) = g CaO
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Answer:

mass is 4.57 g

Explanation:

Ca(OH)₂ solution consists of Ca(OH)₂ solute molecules and solvent and we are asked to find the mass of Ca(OH)₂ in the solution

number of moles of Ca(OH)₂ is - 0.0787 mol

molar mass of Ca(OH)₂ is - 58.093 g/mol

we can use the following equation

number of moles = mass of Ca(OH)₂ / molar mass of Ca(OH)₂

rearranging the equation

mass of Ca(OH)₂ = number of moles x molar mass

 mass = 0.0787 mol x 58.093 g/mol = 4.57 g

mass of Ca(OH)₂ is 4.57 g

4 0
3 years ago
A chemist prepares a solution of iron chloride by measuring out of into a volumetric flask and filling to the mark with distille
myrzilka [38]

Complete Question:

A chemist prepares a solution of iron chloride by measuring out 0.10 g of FeCl2 into a 50. mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of anions in the chemist's solution.

Answer:

[Fe+] = 0.0156 M

[Cl-] = 0.0316 M

Explanation:

The molar mass of iron chloride is 126.75 g/mol, thus, the number of moles presented in 0.10 g of it is:

n = mass/molar mass

n = 0.10/126.75

n = 7.89x10⁻⁴ mol

In a solution, it will dissociate to form:

FeCl2 -> Fe+  + 2Cl-

So, the stoichiometry is 1:1:2, and the number of moles of the ions formed are:

nFe+ = 7.89x10⁻⁴ mol

nCl- = 2*7.89x10⁻⁴  = 1.58x10⁻³ mol

The molarity is the number of moles divided by the solution volume, in L (50.0 mL = 0.05 L):

[Fe+] = 7.89x10⁻⁴/0.05 = 0.0156 M

[Cl-] = 1.58x10⁻³/0.05 = 0.0316 M

5 0
3 years ago
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