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Marina CMI [18]
3 years ago
6

La masa de una olla es de 300g y contiene 90% de aluminio. Hallar el número de moles de aluminio de la olla. P.A.(Al= 27)

Chemistry
1 answer:
Neko [114]3 years ago
6 0

Explanation:

The mass of a pot is 300g and contains 90% aluminum. Find the number of moles of aluminum in the pot. P.A. (Al = 27)

The mass of aluminum present in the pot is:

300 g * 90/100\\=270 g

Hence, in the given pot 270g Al is present.

Number of moles of Al=\frac{given mass ofAl}{its molar mass}

The gram atomic mass of Al -27 g/mol

Given the mass of Al is 270 g

Substitute these values in the above formula:

Number of moles of Al=\frac{given mass ofAl}{its molar mass}\\=\frac{270 g}{27 g} \\=10.0 mol

Answer is 10.0 mol of Al is present.

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The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium
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The concentration is C = 1.11 mol/L

Explanation:

From the question we are told that

     The absorbance is  A = 0.347

       The length is  l =  447 nm  =  447 *10^{-7} \ cm

     

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substituting values

        C = \frac{0.347}{7.0*10^{3} *  447 *10^{-7}  }

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