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2 years ago

Solve a problem.

Physics

1 answer:

olasank [31]2 years ago

5 0

Explanation:

Height of object =5cm

Position of object, u=−25cm

Focal length of the lens, f=10cm

Position of image, v=?

We know that,

−

So,

(5−2)

That is,

So,

=16.66cm

Thus, distance of image is 16.66cm on the opposite side of lens.

Now, magnification =

That is,

−25

16.66

=−0.66

Also,

heightofobject

heightofimage

−0.66=

5cm

heightofimage

Therefore, Height of image =3.3cm

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