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2 years ago

Solve a problem.

Physics

1 answer:

olasank [31]2 years ago

5 0

Explanation:

Height of object =5cm

Position of object, u=−25cm

Focal length of the lens, f=10cm

Position of image, v=?

We know that,

−

So,

(5−2)

That is,

So,

=16.66cm

Thus, distance of image is 16.66cm on the opposite side of lens.

Now, magnification =

That is,

−25

16.66

=−0.66

Also,

heightofobject

heightofimage

−0.66=

5cm

heightofimage

Therefore, Height of image =3.3cm

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An object that weighs 2.450 N is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period o

Viktor [21]

Answer:

Spring constant, k = 24.1 N/m

Explanation:

Given that,

Weight of the object, W = 2.45 N

Time period of oscillation of simple harmonic motion, T = 0.64 s

To find,

Spring constant of the spring.

Solution,

In case of simple harmonic motion, the time period of oscillation is given by :

$T=2\pi\sqrt{\dfrac{m}{k}}$

m is the mass of object

$m=\dfrac{W}{g}$

$m=\dfrac{2.45}{9.8}$

m = 0.25 kg

$k=\dfrac{4\pi^2m}{T^2}$

$k=\dfrac{4\pi^2\times 0.25}{(0.64)^2}$

k = 24.09 N/m

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3 years ago

Quick does the watermelon have more or less mass then the 2kg bottle?

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Answer

it will be less\

Explanation:

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3 years ago

During the process of mountain building, earthquakes sometimes occur along continental-continental convergent boundaries. Which

elena-14-01-66 [18.8K]

Answer:

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3 years ago

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You walk towards Starbucks southward for 14 meters and then west for 9 meters. The trip takes you 3 minutes to walk there. What

zimovet [89]

Although you walked (14+9)= 23 meters of distance, you ended up only 16.64 meters from where you started. That's your "displacement".

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3 years ago

The stopping sight distance for a car traveling at 50 mph is 461 ft (including both perception-reaction distance and braking dis

Ivan

Answer:

2.08 s

Explanation:

We are given that

Speed,v=50mph=73.3ft/s

1 mile=5280 feet

1 hour=3600 s

Distance,d=461 ft

t=2.5 s

v'=60 mph=88 ft/s

We have to find the perception reaction time.

Perception reaction distance= $d_p=vt=73.3\ti es 2.5=183.25 feet$

$d_p=d'_p$

$d'_p=v't$

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4 0

3 years ago