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2 years ago

Solve a problem.

Physics

1 answer:

olasank [31]2 years ago

5 0

Explanation:

Height of object =5cm

Position of object, u=−25cm

Focal length of the lens, f=10cm

Position of image, v=?

We know that,

−

So,

(5−2)

That is,

So,

=16.66cm

Thus, distance of image is 16.66cm on the opposite side of lens.

Now, magnification =

That is,

−25

16.66

=−0.66

Also,

heightofobject

heightofimage

−0.66=

5cm

heightofimage

Therefore, Height of image =3.3cm

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The path of the earth around the sun is an ellipse with the sun at one focus. The ellipse has a major axis of 186,000,000 miles

Charra [1.4K]

Answer:

a) $r = 182838000\,mi$ , b) $r = 189162000\,mi$

Explanation:

a) The distance between the center and one of the foci is:

$c = \epsilon \cdot a$

$c = (0.017)\cdot (186000000\,mi)$

$c = 3162000\,mi$

The shortest distance is:

$r = a - c$

$r = 186000000\,mi -3162000\,mi$

$r = 182838000\,mi$

b) The longest distance is:

$r = a + c$

$r = 186000000\,mi +3162000\,mi$

$r = 189162000\,mi$

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3 years ago

A 2.1-mF capacitor is discharged through a 4.0-kΩ resistor. How long will it take for the capacitor to lose half its initial sto

Harrizon [31]

Answer:

the answer is a)5.82s

Explanation:

Hello!

The first thing we must understand to solve this exercise is that a capacitor has the following characteristic function

$V=(Vo)e^{-t/RC}$

where

Vo=initial voltage

V=voltage in an instant of time

t=time

R=resistance=4000Ω

C=capacitance=2.1-mF=0.0021F

we must consider that the final voltage is half of the initial voltage so we deduce the following equation

V=Vo/2

Now we replace in the initial equation, and start an algebraic process to find t

$\frac{Vo}{2} =(Vo)e^{-t/RC}\\0.5=e^{-t/RC}\\ln(0.5)=ln(e^{-t/RC})\\ln(0.5)=\frac{-t}{RC} \\t=-(RC)ln0.5$

finally with the equation ready, we use the resistance and capacitance values to find the time value

$t=-(4000)(0.0021)ln(0.5)=5.82s$

the answer is a)5.82s

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2 years ago

Given 4.8 moles of a gas at 37 degrees Celsius and at 792 torr, what is the volume of the gas? (The ideal gas constant is 0.0821

Anastaziya [24]

Answer:

1.17 x 10^2 L

Explanation:

We can find the volume of the gas by using the ideal gas law:

$pV=nRT$

where we have:

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V is the volume

n = 4.8 mol is the number of moles

R = 0.0821 L · atm/mol · K is the ideal gas constant

$T=37^{\circ}+273 =310 K$ is the temperature

Solving the equation for V, we find the volume

$V=\frac{nRT}{p}=\frac{(4.8 mol)(0.0821 L atm/mol K)(310 K)}{1.04 atm}=117.5 L = 1.17\cdot 10^2 L$

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3 years ago