The final velocity of the train at the end of the given distance is 7.81 m/s.
The given parameters;
- initial velocity of the train, u = 6.4 m/s
- acceleration of the train, a = 0.1 m/s²
- distance traveled, s = 100 m
The final velocity of the train at the end of the given distance is calculated using the following kinematic equation;
v² = u² + 2as
v² = (6.4)² + (2 x 0.1 x 100)
v² = 60.96
v = √60.96
v = 7.81 m/s
Thus, the final velocity of the train at the end of the given distance is 7.81 m/s.
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Answer:

Explanation:
We can use the equation for the speed

where x is the distance and t the time. In this case we know that the time spent was 2 hours and the distance was 150km. By replacing we have

I hope this useful for you
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Answer:
The gravitational potential energy of the two-sphere system just as B is released is
U = -[(G)(MA)(MB)/x₁]
where G = Gravitational constant
G = (6.7 × 10⁻¹¹) Nm²/kg²
Explanation:
The gravitational potential energy of two masses (m and M), separated by a distance, d, is given as
U = -(GMm/d)
For our question,
Mass of object 1 = MA
Mass of object 2 = MB
Distance between them = x₁
U = -[(G)(MA)(MB)/x₁]
where G = Gravitational constant
G = (6.7 × 10⁻¹¹) Nm²/kg²
Hope this Helps!!!
None of the diagrams you attached shows the scenario accurately,
or at all.
Heat flows from Object-B to Object-A, until both objects are at
the same temperature, somewhere between 10°C and 29°C.