Answer:
t = 30 s
d = 1125 m
Explanation:
t = v/a = 75/2.5 = 30 s
d = v²/2a = 75²/(2(2.5)) = 1125 m
or
d = ½at² = ½(2.5)30² = 1125 m
For a 650-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth’s mean radius, the resultant values are is mathematically given as
- V=5.59*10^3m/s
- T=3.98hours
- F=1.47*10^3N
<h3>What are the satellite’s orbital speed, the period of its revolution, and the gravitational force acting on it.?</h3>
Generally, the equation for satellite orbital speed is mathematically given as
a)

V=5.59*10^3m/s
b)

T=3.98hours
c)

Therefore

F=1.47*10^3N
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Explanation:
The answer is In the picture. Thanks.
The given question is incomplete. The complete question is as follows.
In a nuclear physics experiment, a proton (mass
kg, charge +e =
C) is fired directly at a target nucleus of unknown charge. (You can treat both objects as point charges, and assume that the nucleus remains at rest.) When it is far from its target, the proton has speed
m/s. The proton comes momentarily to rest at a distance
m from the center of the target nucleus, then flies back in the direction from which it came. What is the electric potential energy of the proton and nucleus when they are
m apart?
Explanation:
The given data is as follows.
Mass of proton =
kg
Charge of proton = 
Speed of proton = 
Distance traveled = 
We will calculate the electric potential energy of the proton and the nucleus by conservation of energy as follows.
=

where, 
U = 
Putting the given values into the above formula as follows.
U = 
= 
= 
Therefore, we can conclude that the electric potential energy of the proton and nucleus is
.
Technically, we can't answer the question with the given information.
Even though the cart's speed is constant, it may be turning an corner,
or driving along a curved path. If it's not driving in a straight, then there
must be some force acting on it.
If the cart IS driving in a straight line, AND its speed is constant, then
there can't be any net force acting on it. In that case, the correct choice
is ' B '. (I'm sure this is right IF the cart is driving in a straight line.)