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mixer [17]
3 years ago
14

The labeled images each represent the wave patterns found in the electromagnetic wave spectrum. which of these images are correc

tly labeled for frequency, wave length, and radiant energy?

Physics
1 answer:
Phantasy [73]3 years ago
5 0
Energy E of EM radiation is given by the equation E=hf, where h is Planck's constant and f is frequency. It means energy E and frequency f are proportional so as we increase the frequency, energy also increases. Also, the relationship between the wavelength and frequency is c=λ*f where λ is the wavelength and f is frequency and c is the speed of light. This tells us the wavelength and frequency are inversely proportional. So as we increase the frequency the wavelength is getting smaller. So as we go from left to right the frequency increases, energy also increases and the wavelength is decreasing. Or, on the left side we should have low frequency, low radiant energy, and long wavelength. On the right side we should have high frequency, high radiant energy and low wavelength. That is the third graph. 
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Answer:

10

Explanation:

15 cm minus 5 cm

5 0
2 years ago
In 0.60 seconds, a projectile goes from 0 to 610 m/s. What is the acceleration of the projectile?
IceJOKER [234]

Answer: a=1016.66 m/s^{2}

Explanation:

Acceleration a is expressed in the following formula:

a=\frac{V_{f}-V_{o}}{t}

Where:

V_{f}=610 m/s is the final velocity of the projectile

V_{o}=0 m/s  is the initial velocity of the projectile

t=0.6 s is the time

Solving:

a=\frac{610 m/s-0 m/s}{0.6 s}

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6 0
3 years ago
Which statement describes the atomic number?<br>​
Vadim26 [7]

Answer:The term atomic number, conventionally denoted by the symbol Z, indicates number of protons present in the nucleus of an atom, which is also equal to the number of electrons in an uncharged atom. The number of neutrons is represented by the neutron number (N)

Explanation:

6 0
2 years ago
If your car runs out of gas and you must push it 250 m to the nearest gas station. How much work is done on the car if it is pus
tankabanditka [31]

Answer:

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Suppose that light from a laser with wavelength 633 nm is incident on a thin slit of width 0.500 mm. If the diffracted light pro
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Explanation:

It is given that,

Wavelength, \lambda=633\ nm=633\times 10^{-9}\ m

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3 years ago
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