All categories

3 years ago

A parking garage charges $2 to enter the garage and $1.50 an hour to park.

2 answers:

5 0

It would take 4 hours

For the first hour you'd pay $5 at A and $6.50 at B
For the second hour you'd pay $7 at A and $8 at B
For the third hour you'd pay $9 at A and 9.50 at B
And for the fourth hour you'd pay $11 at A and $11 at B

Karolina [17]3 years ago

3 0

How many hours are you "parked?"

You might be interested in

Write an equation that represents the line. use exact numbers.

nekit [7.7K]

Answer The line two origins are 6 and 5.1

Step-by-step explanation:

Hope this helps ^^

3 0

3 years ago

Please help me, I'm doing a test.

Tju [1.3M]

Answer:

(3,4)

Step-by-step explanation:

first you're going to solve the equation -2x

your equation should now be: $\left \{ {{-2x+3y\\=6} \atop {-2x=2-2y}} \right.$

next you're going to substitute the given value of -2x into the equation $-2x+3y=6$

so your equation should now be: $2-2y+3y=6$

next you're going to solve the equation for y

equation should now be: y=4

than you're going to substitute the given value of y into the equation $-2x=2-2$ × $4$

then you're going to solve the equation for x

your equation should now be: x=3

then the possible solution of the system is the order pair: (x,y)=(3,4)

4 0

2 years ago

Factor 4x^2 - 25 show your work Help Plz!

r-ruslan [8.4K]

<span>4x^2 - 25
= (2x)^2 - 5^2 .................using a^2 - b^2 = (a+b)(a-b)
= (2x + 5)(2x - 5)</span>

4 0

2 years ago

Help? don't know what to pick, and please dont choose randomly

Yakvenalex [24]

Answer:

yess!!!

step-by-step explained.

......

6 0

3 years ago

Read 2 more answers

Simplify the expression csc(-x)/1+tan^2x)

Charra [1.4K]

Assuming ya meant $\frac{csc(-x)}{1+tan^2(x)}$

to slimplify, we use a variation of the pythagorean identity and a decomposition into the sin and cos

for the pythaogreaon identity
$cos^2(x)+sin^2(x)=1$
divide both sides by $cos^2(x)$
$1+tan^2(x)=sec^2(x)$ since $\frac{sin(x)}{cos(x)}=tan(x)$
subsitute
$\frac{csc(x)}{sec^2(x)}$

recall that $csc(x)=\frac{1}{cos(x)}$
also that cos(x) is an even function and thus cos(-x)=cos(x)
therfore $csc(-x)=\frac{1}{cos(-x)}=\frac{1}{cos(x)}=csc(x)$
so we get

$\frac{csc(x)}{sec^2(x)}$
decompose them into $\frac{1}{cos(x)}$ and $\frac{1}{sin^2(x)}$ to get $\frac{\frac{1}{cos(x)}}{\frac{1}{sin^2(x)}}$
multiply by $\frac{sin^2(x)}{sin^2(x)}$ to get
$\frac{sin^2(x)}{cos(x)}$
we can furthur simlify to get
$(\frac{sin(x)}{cos(x)})(sin(x))=tan(x)sin(x)$
the expression simplifies to tan(x)sin(x)

5 0

3 years ago

Read 2 more answers