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Nady [450]
4 years ago
5

A parking garage charges $2 to enter the garage and $1.50 an hour to park.

Mathematics
2 answers:
Nostrana [21]4 years ago
5 0
It would take 4 hours 

For the first hour you'd pay $5 at A and $6.50 at B
For the second hour you'd pay $7 at A and $8 at B 
For the third hour you'd pay $9 at A and 9.50 at B
And for the fourth hour you'd pay $11 at A and $11 at B

Karolina [17]4 years ago
3 0
How many hours are you "parked?"
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Step-by-step explanation:

- 3 ( x + 2 ) + 9 + 7x = 4x + 5 - 2

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3 years ago
Can someone show work for this problem, I need it I only have the answer...
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3 years ago
Which measure of center would you use to compare the populations represented by the box plots?
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Step-by-step explanation:

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4 0
4 years ago
Read 2 more answers
The dollar value of a car is a function f, . of the number of years, t, since the car was purchased. Thefunction is defined by t
Fofino [41]

Given the following question:

f(t)=12000\times(\frac{3}{5})^t

Part A:

I believe that the 12,000 tells us the orginal price of the car, or the price the car was purchased for. 12000 is the orginal price of the car.

Part B:

I believe that the 3/5 tells us the decline in value each year after the car has been purchased. Which is why t is the exponet is t was 2 you would have to multiply 3/5 by itself twice and then multiply it by 12000 which further decreases it's value. 3/5 represents the decline in value after T years.

Part C:

t = number of years

t = 3

\begin{gathered} f(t)=12000\times\frac{3}{5^{}}^3 \\ \frac{3}{5}^3=\frac{3}{5}\times\frac{3}{5}\times\frac{3}{5} \\ \frac{3}{5}\times\frac{3}{5}=\frac{9}{25} \\ \frac{9}{25}\times\frac{3}{5}=\frac{27}{125} \\ 12000\times\frac{27}{125}=2592 \\ v=2592 \end{gathered}

Value of the car after three years will be 2592.

4 0
2 years ago
How to solve this question
AlexFokin [52]

Divide 141 by 3, that’s 47. Now subtract 47 from 141 and you get 94. 94 of the figures are not sports related. The answer is B.

7 0
3 years ago
Read 2 more answers
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