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patriot [66]
4 years ago
8

In connective tissue, the role of elastic fibers is to __________.

Physics
1 answer:
blagie [28]4 years ago
6 0
The role of elastic fiber is to keep the tissue length(or elasticity). That means if the tissue is stretched the elastic fiber will exert force to make it back into the normal length. This fiber can be found<span> in skin and lack of it will make wrinkle. Other connective tissue would be collagen which will give strength</span>
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Which of the following is the brightness of a star as we see if from Earth?
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A heavy flywheel is accelerated (rotationally) by a motor that provides constant torque and therefore a constant angular acceler
ki77a [65]

Answer:

a)t_1=\frac{w_1-w_o}{\alpha}=\frac{w_1}{\alpha}sec

b)\theta_1=\frac{w_1^2}{2\alpha}rad

c)t_2=\frac{\alpha t_1}{5\alpha}=\frac{t_1}{5}sec

Explanation:

1) Basic concepts

Angular displacement is defined as the angle changed by an object. The units are rad/s.

Angular velocity is defined as the rate of change of angular displacement respect to the change of time, given by this formula:

w=\frac{\Delat \theta}{\Delta t}

Angular acceleration is the rate of change of the angular velocity respect to the time

\alpha=\frac{dw}{dt}

2) Part a

We can define some notation

w_o=0\frac{rad}{s},represent the initial angular velocity of the wheel

w_1=?\frac{rad}{s}, represent the final angular velocity of the wheel

\alpha, represent the angular acceleration of the flywheel

t_1 time taken in order to reach the final angular velocity

So we can apply this formula from kinematics:

w_1=w_o +\alpha t_1

And solving for t1 we got:

t_1=\frac{w_1-w_o}{\alpha}=\frac{w_1}{\alpha}sec

3) Part b

We can use other formula from kinematics in order to find the angular displacement, on this case the following:

\Delta \theta=wt+\frac{1}{2}\alpha t^2

Replacing the values for our case we got:

\Delta \theta=w_o t+\frac{1}{2}\alpha t_1^2

And we can replace t_1from the result for part a, like this:

\theta_1-\theta_o=w_o t+\frac{1}{2}\alpha (\frac{w_1}{\alpha})^2

Since \theta_o=0 and w_o=0 then we have:

\theta_1=\frac{1}{2}\alpha \frac{w_1^2}{\alpha^2}

And simplifying:

\theta_1=\frac{w_1^2}{2\alpha}rad

4) Part c

For this case we can assume that the angular acceleration in order to stop applied on the wheel is \alpha_1 =-5\alpha \frac{rad}{s}

We have an initial angular velocity w_1, and since at the end stops we have that w_2 =0

Assuming that t_2 represent the time in order to stop the wheel, we cna use the following formula

w_2 =w_1 +\alpha_1 t_2

Since w_2=0 if we solve for t_2 we got

t_2=\frac{0-w_1}{\alpha_1}=\frac{-w_1}{-5\alpha}

And from part a) we can see that w_1=\alpha t_1, and replacing into the last equation we got:

t_2=\frac{\alpha t_1}{5\alpha}=\frac{t_1}{5}sec

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The wavelength of the wave in the diagram below is given by letter ____ and the amplitude of the wave in the diagram below given
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Answer:

A scientific law is a statement that summarizes a pattern found in nature.

Explanation:

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