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tekilochka [14]
4 years ago
12

How far will a ball travel that goes 35 meters per second for 18 seconds?

Physics
1 answer:
katen-ka-za [31]4 years ago
7 0
Theoretically, 35 x 18 = 630
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Xander was traveling at a final velocity of 4.5 m/s for 3.5 seconds. Finley was traveling at a final velocity of 3.6 m/s for 4.2
Dima020 [189]

the answer is Finley, Xander, Max

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True or False. Where an element is located on the periodic table can help predict some of its properties.
lubasha [3.4K]
It’s true there are sections in the periodic table that define the elements.
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3 years ago
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Equations to use: v= λ ∙ f v=d/t
Margarita [4]

b. 460.8 m/s

Explanation:

The relationship between the speed of the wave along the string, the length of the string and the frequency of the note is

f=\frac{v}{2L}

where v is the speed of the wave, L is the length of the string and f is the frequency. Re-arranging the equation and substituting the data of the problem (L=0.90 m and f=256 Hz), we can find v:

v=2Lf=2(0.90 m)(256 Hz)=460.8 m/s

c. 18,000 m

Explanation:

The relationship between speed of the wave, distance travelled and time taken is

v=\frac{d}{t}

where

v = 6,000 m/s is the speed of the wave

d = ? is the distance travelled

t = 3 s is the time taken

Re-arranging the formula and substituting the numbers into it, we find:

d=vt=(6,000 m/s)(3 s)=18,000 m

3 0
3 years ago
A 240 m long segment of wire is hanging between 2 transmission lines. What is the total magnetic force only (ignore gravitationa
Delvig [45]

Answer:

<em>7.2 N</em>

Explanation:

length of wire L  = 240 m

current I = 500 A

field strength B = 3 x 10^-5 T

magnetic force on a current carrying conductor F is given as

F = BILsin∅

The wires are perpendicular with field therefore sin∅ = sin 90° = 1

therefore,

F = BIL = 3 x 10^-5 X 500 X 240 = 3.6 N

<em>If the wire exists between this two transmission lines, then total magnetic force on the wire = 2 x 3.6 = 7.2 N</em>

7 0
3 years ago
11. A car is pulled with a force of 10,000 N. The car's mass is 1267 kg. But, the car covers 394.6 m in 15 seconds.
aleksklad [387]

Answer:

A) a = 7.89 m/s²

B) a = 3.51 m/s²

C) 4.38 m/s²

D) Frictional force

E) F_f = 5552.83 N

Explanation:

A) Formula for Force is;

F = ma

Where;

m is mass

a is acceleration

We are given;

F = 10,000 N

m = 1267 kg

Thus;

10000 = 1267a

a = 10000/1267

a = 7.89 m/s²

B) We are told the car covers 394.6 m in 15 seconds.

Using Newton's third equation equation of motion, we can find the actual acceleration.

s = ut + ½at²

u is zero since the object began from rest.

Thus;

S = ½at²

394.6 = ½ × a × 15²

a = 394.6 × 2/225

a = 3.51 m/s²

C) difference in accelerations = 7.89 - 3.51 = 4.38 m/s²

D) The force that caused the difference in acceleration is frictional force

E) To find the magnitude of the force that caused the difference in acceleration, we will use the formula;

F - F_f = ma

F_f = F - ma

Where F_f is the frictional force

Thus;

F_f = 10000 - 1267(3.51)

F_f = 5552.83 N

7 0
3 years ago
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