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3 years ago

A voltmeter is a device that measures _____.

2 answers:

5 0

A voltmeter its instrument used for measuring electrical potential difference between two points in an electric circuit. An ammeter is a measuring device used tomeasure the electric current in a circuit.

liubo4ka [24]3 years ago

4 0

It measures the potential difference (voltage)

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What is the single most important factor that determines why Earth (or almost any planet in the Solar System) experiences season

kirill [66]

Answer:

Planetary seasons are caused by two factors:

1. axial tilt and

2. variable distance from the sun

Explanation:

Earth's orbit is nearly circular and so has little effect on climate. It's our planet's axial tilt that causes almost all seasonal changes.

You can read further; Planetary seasons

6 0

3 years ago

If a person has the genotype Rr for hair where red is dominant to blue, what phenotype would this person have?

JulijaS [17]

the person's phenotype would be red hair. phenotype is what you see on the outside, genotype is what the dna says. <3

4 0

2 years ago

An infnitely long metal cylinder rotates about its symmetry axis with an angular velocity omega. The cylinder is charged. The ch

Klio2033 [76]

Answer:

$B = \frac{\mu_0 \rho r^2 \omega}{2}$

Explanation:

Let the position of the point where magnetic field is to be determined is at distance "r" from the axis of cylinder

so here total charge lying in this region is

$q = \rho(\pi r^2 L)$

now magnetic field inside the cylinder is given as

$B = \frac{\mu_0 N i}{L}$

here current is given as

$i = \frac{q\omega}{2\pi}$

$i = \frac{\rho (\pi r^2 L) \omega}{2\pi}$

$i = \frac{\rho r^2 L \omega}{2}$

now magnetic field is given as

$B = \frac{\mu_0 \rho r^2 L \omega}{2L}$

$B = \frac{\mu_0 \rho r^2 \omega}{2}$

5 0

3 years ago

Which one is series and which one is parallel ( i give 20 points who answer )

slega [8]

Answer:

figure (a) L1 is series and L2 is parallel to L3

figure (b) L2 and L3 are parallel to L1

4 0

2 years ago

Two tiny, spherical water drops, with identical charges of -4.29 Ã 10-16 C, have a center-to-center separation of 0.845 cm. A) W

RSB [31]

Answer:

Electrostatic force, $F=2.31\times 10^{-17}\ N$

Number of electrons, n = 2681 electrons

Explanation:

Given that,

Charges, $q_=q_2=-4.29\times 10^{-16}\ C$

Separation between charges, $r=0.845\ cm=0.845\times 10^{-2}\ m$

(a) Let F is the magnitude of the electrostatic force acting between them. The electric force between charges is given by :

$F=\dfrac{kq^2}{r^2}$

$F=\dfrac{9\times 10^9\times (4.29\times 10^{-16})^2}{(0.845\times 10^{-2})^2}$

$F=2.31\times 10^{-17}\ N$

(b) Let n be the excess electrons on each drop, giving it its charge imbalance. It can be calculated using quantization of electric charge as :

$q=ne$

$n=\dfrac{q}{e}$

$n=\dfrac{4.29\times 10^{-16}}{1.6\times 10^{-19}}$

n = 2681.25 electrons

n = 2681 electrons

So, the number of excess electrons on each drop is 2681 electrons. Hence, this is the required solution.

4 0

3 years ago