An expertly designed format for arranging, processing, accessing, and storing data is called a data structure.
Data structures come in both simple and complex forms, all of which are made to organize data for a certain use. Users find it simple to access the data they need and use it appropriately thanks to data structures. The organizing of information is framed by data structures in a way that both machines and people can better grasp. A data structure may be chosen or created in computer science and computer programming to store data in order to be used with different methods. In some circumstances, the design of the data structure and the algorithm's fundamental operations are closely related. Each data structure comprises information about the data values, relationships between the data and — in some situations — functions that can be applied to the data. For instance, in an object-oriented programming language, the data structure and its related methods are tied together as part of a class description. Although they may be designed to operate with the data structure in non-object oriented languages, these functions are not considered to be a part of the data structure. A data structure may be chosen or created in computer science and computer programming to store data in order to be used with different methods. In some circumstances, the design of the data structure and the algorithm's fundamental operations are closely related. Each data structure comprises information about the data values, relationships between the data and — in some situations — functions that can be applied to the data.
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Answer:
Explanation:
Using the expression shown below as:
Where,
is the number of vacancies
N is the number of defective sites
k is Boltzmann's constant = 
is the activation energy
T is the temperature
Given that:
N = 10 moles
1 mole = 
So,
N = 
Temperature = 425°C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (425 + 273.15) K = 698.15 K
T = 698.15 K
Applying the values as:
![ln[\frac {2.3}{6.023}\times 10^{-11}]=-\frac {Q_v}{1.38\times 10^{-23}\times 698.15}](https://tex.z-dn.net/?f=ln%5B%5Cfrac%20%7B2.3%7D%7B6.023%7D%5Ctimes%2010%5E%7B-11%7D%5D%3D-%5Cfrac%20%7BQ_v%7D%7B1.38%5Ctimes%2010%5E%7B-23%7D%5Ctimes%20698.15%7D)
Answer:
275 Kelvin
Explanation:
Coefficient of Performance=11
Answer:
The question has some details missing : The 35-kg block A is released from rest. Determine the velocity of the 13-kgkg block BB in 4 ss . Express your answer to three significant figures and include the appropriate units. Enter positive value if the velocity is upward and negative value if the velocity is downward.
Explanation:
The detailed steps and appropriate calculation is as shown in the attached file.
