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HACTEHA [7]
3 years ago
14

Gas chromatography separates compounds depending on their__________ . Benzene, m-xylene, and toluene have similar_________ , the

refore, the main basis for separation is_______ . The more volatile a component the_______ , hence the more time it spends in the________ , giving it a________ retention time. Therefore, components of a liquid mixture will elute in order of_________ .
Engineering
1 answer:
amm18123 years ago
3 0

Answer and Explanation:

Gas chromatography separates compounds depending on their **polarity and volatility**. Benzene, m-xylene, and toluene have similar **polarities**, therefore, the main basis for separation is **volatility**. The more volatile a component the ** higher its vapor pressure**, hence the more time it spends in the **gaseous mobile phase**, giving it a **shorter** retention time. Therefore, components of a liquid mixture will elute in order of **increasing boiling points/decreasing volatilities/increasing polarities with the stationary phase**.

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8.19 - Airline Reservations System (Project Name: Airline) - A small airline has just purchased a computer for its new automated
e-lub [12.9K]

Answer:

The App is written in C++ language using dev C++.

Explanation:

/******************************************************************************

You can run this program in any C++ compiler like dev C++ or any online C++ compiler

*******************************************************************************/

#include <iostream>

using namespace std;

class bookingSeat// class for airline reservation system

{

  private:

   

   

  bool reserveSeat[10];// 10 seats (1-5) for first class and 6-10 for economy class

  int firstClassCounter=0;//count first class seat

  int economyClassCounter=5;//count economy class seat

  char seatPlacement;/* switch between economy and first clas seat----- a variable for making decision based on user input*/

  public:  

  void setFirstClassSeat()//

  {

      if(firstClassCounter<5)// first class seat should be in range of 1 to 5

      {

          reserveSeat[firstClassCounter]=1; /*set first class seat..... change index value to 1 meaning that it now it is reserved*/

          cout<<"Your First Class seat is booked and your seat no is "<<firstClassCounter+1; //display seat number reserved

          firstClassCounter++; //increament counter

      }

      else//in case seats are ful

      {

          cout<<"\nSeats are full";

          if(economyClassCounter==10 && firstClassCounter==5)

          {

              cout<<"\n Next flight leaves in 3 hours.";

          }

          else

          {

              cout<<"\nIt’s acceptable to be placed to you in the first-class section  y/n ";//take input from user

              cin>>seatPlacement;//user input

              if(seatPlacement=='y')//if customer want to reserve seat in first class

              {

                  setEconomyClassSeat();// then reserve first class seat

              }

              else

              {

                  cout<<"\n Next flight leaves in 3 hours.";

               }

               

          }

      }

       

  }

  void setEconomyClassSeat()//set economy class seat

  {

    if(economyClassCounter<10)//seat ranges between 6 and 10

      {

          reserveSeat[economyClassCounter]=1;// reserve economy class seat

          cout<<"Your Economy class seat is booked and your seat no is "<<economyClassCounter+1;//display reservation message about seat

          economyClassCounter++;//increament counter

      }

      else// if economy class seats are fulled

      {

          cout<<"\nSeats are full";

          if(economyClassCounter==10 && firstClassCounter==5)//check if all seats are booked in both classes

          {

              cout<<"\n Next flight leaves in 3 hours.";

          }

          else

          {

              cout<<"\nIt’s acceptable to be placed to you in the first-class section  y/n ";//take input from user

              cin>>seatPlacement;//user input

              if(seatPlacement=='y')//if customer want to reserve seat in first class

              {

                  setFirstClassSeat();// then reserve first class seat

              }

              else

              {

                  cout<<"\n Next flight leaves in 3 hours.";

               }

               

          }

      }

  }

   

   

};

int main()

{   int checkseat=10;// check seat

   int classType;//class type economy or first class

   bookingSeat bookseat;//object declaration of class bookingSeat

   while(checkseat<=10)//run the application until seats are fulled in both classes

   {

       cout<<"\nEnter 1 for First Class and 2 for Economy Class ";

       cin>>classType;//what user entered

       switch (classType)//decide which seat class to be reserved  

       {

           case 1://if user enter 1 then reserve first class seat

           bookseat.setFirstClassSeat();

           break;

           case 2://if user enter 2 then reserve the economy class seat

           bookseat.setEconomyClassSeat();

           

       }

       

   }

   

   return 0;

}

8 0
2 years ago
A horizontal curve of a two-lane undivided highway (12-foot lanes) has a radius of 678 feet to the center line of the roadway. A
OLEGan [10]

Answer:

maximum speed for safe vehicle operation = 55mph

Explanation:

Given data :

radius ( R ) = 678 ft

old building located ( m )= 30 ft

super elevation = 0.06

<u>Determine the maximum speed for safe vehicle operation </u>

firstly calculate the stopping sight distance

m = R ( 1 - cos \frac{28.655*S}{R} )  ----  ( 1 )

R = 678  

m ( horizontal sightline ) = 30 ft

back to equation 1

30 = 678 ( 1 - cos (28.655 *s / 678 ) )

( 1 - cos (28.655 *s / 678 ) )  = 30 / 678 = 0.044

cos \frac{28.65 *s }{678}  = 1.044

hence ; 28.65 * s = 678 * 0.2956

s = 6.99 ≈ 7 ft

next we will calculate the design speed ( u ) using the formula below

S = 1.47 ut  + \frac{u^2}{30(\frac{a}{3.2} )-G1}  ----  ( 2 )

t = reaction time,  a = vehicle acceleration, G1 = grade percentage

assuming ; t = 2.5 sec , a = 11.2 ft/sec^2, G1 = 0

back to equation 2

6.99 = 1.47 * u * 2.5 + \frac{u^2}{30[(11.2/32.2)-0 ]}

3.675 u  + 0.0958 u^2 - 6.99 = 0

u ( 3.675 + 0.0958 u ) = 6.99

5 0
2 years ago
determine the optimum compressor pressure ratio specific thrust fuel comsumption 2.1 220k 1700k 42000 1.004
Afina-wow [57]

Answer:

hello your question is incomplete attached below is the complete question

A) optimum compressor ratio = 9.144

B) specific thrust = 2.155 N.s /kg

C) Thrust specific fuel consumption = 1670.4 kg/N.h

Explanation:

Given data :

Mo = 2.1 ,  To = 220k , Tt4 = 1700 k, hpr = 42000 kj/kg, Cp = 1.004 kj/ kg.k

γ = 1.4

attached below is the detailed solution

6 0
2 years ago
A patient has swollen feet, ankles, and legs, and has pain in his lower back. Tests show the level of urea, a waste product, in
myrzilka [38]

Answer: B  Excretory

Explanation: Hope this helps :)

3 0
2 years ago
A rigid tank contains 2 kg of N2 and 4 kg of Co2 at temperature of 25 C and 1 MPa. Find the partial pressure of each gas respect
lions [1.4K]

Answer: Partial pressures are 0.6 MPa for nitrogen gas and 0.4 MPa for carbon dioxide.

Explanation: <u>Dalton's</u> <u>Law</u> <u>of</u> <u>Partial</u> <u>Pressure</u> states when there is a mixture of gases the total pressure is the sum of the pressure of each individual gas:

P_{total} = P_{1}+P_{2}+...

The proportion of each individual gas in the total pressure is expressed in terms of <u>mole</u> <u>fraction</u>:

X_{i} = moles of a gas / total number moles of gas

The rigid tank has total pressure of 1MPa.

  • Nitrogen gas:

molar mass = 14g/mol

mass in the tank = 2000g

number of moles in the tank: n=\frac{2000}{14} = 142.85mols

  • Carbon Dioxide:

molar mass = 44g/mol

mass in the tank = 4000g

number of moles in the tank: n=\frac{4000}{44} = 90.91mols

Total number of moles: 142.85 + 90.91 = 233.76 mols

To calculate partial pressure:

P_{i}=P_{total}.X_{i}

For Nitrogen gas:

P_{N_{2}}=1.\frac{142.85}{233.76}

P_{N_{2}} = 0.6

For Carbon Dioxide:

P_{total}=P_{N_{2}}+P_{CO_{2}}

P_{CO_{2}} = P_{total}-P_{N_{2}}

P_{CO_{2}}=1-0.6

P_{CO_{2}}= 0.4

Partial pressures for N₂ and CO₂ in a rigid tank are 0.6MPa and 0.4MPa, respectively.

4 0
2 years ago
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