1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rosijanka [135]
3 years ago
13

How many joules are expended by a 70 kg man climbing up 6m of stairway? How much work is done if the climbing takes place on the

surface of the moon? (Assume that the acceleration due to gravity on the moon’s surface is 1.6 m/s2
Physics
1 answer:
GuDViN [60]3 years ago
7 0

Answer:

On the earth surface ,W= 4200 J

On the moon surface ,W= 672 J

Explanation:

Given that

mass of the man ,m = 70 kg

Height of the stairway ,h= 6 m

On the earth surface :

We know that acceleration due to gravity at earth ,g= 10 m/s²

The work done by man is given as

W= m g h

Now by putting the values in the above equation we get

W= 70 x 10 x 6 J

W=4200 J

On the moon  surface :

The gravity on the moon ,g= 1.6 m/s²

The work done W

W= 70 x 1.6 x 6 J

W=672 J

On the earth surface ,W= 4200 J

On the moon surface ,W= 672 J

You might be interested in
One of your delivery trucks traveled 1,200 miles on 55 gallons of gas. How many miles per gallon did the truck get? (Round off y
Aleksandr-060686 [28]
The word "Per" means divide

"miles per gallon" is the same as "miles / gallon"

The truck went 1,200 miles
on 55 gallons

1,200 ÷ 55 = 21.81
7 0
3 years ago
Read 2 more answers
Dimension of density <br>​
Rom4ik [11]

Answer:

See the explanation below.

Explanation:

We know that density is defined as the relationship between mass and volume.

Ro = m/V

where:

m = mass [kg]

V = volume [m³]

Therefore Ro is given in:

[kg/m^{3} ]

8 0
2 years ago
Violet light (410 nm) and red light
Leokris [45]

Answer:10.03

Explanation:acellus

7 0
2 years ago
A 120-kg object and a 420-kg object are separated by 3.00 m At what position (other than an infinitely remote one) can the 51.0-
djverab [1.8K]

Answer:

1.045 m from 120 kg

Explanation:

m1 = 120 kg

m2 = 420 kg

m = 51 kg

d = 3 m

Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.

By use of the gravitational force

Force on m due to m1 is equal to the force on m due to m2.

\frac{Gm_{1}m}{y^{2}}=\frac{Gm_{2}m}{\left ( d-y \right )^{2}}

\frac{m_{1}}{y^{2}}=\frac{m_{2}}{\left ( d-y \right )^{2}}

\frac{3-y}{y}=\sqrt{\frac{7}{2}}

3 - y = 1.87 y

3 = 2.87 y

y = 1.045 m

Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.

6 0
3 years ago
Visible light waves are ______ waves<br> A.mechanical <br> B.electromagnetic
motikmotik
B.Electromagnetic
explanation:
4 0
3 years ago
Other questions:
  • Dr Spock would have supported which of the following actions by parents
    10·1 answer
  • As a rocket travels upward from earth, air resistance decreases along with the force of gravity. The rocket's mass also decrease
    15·1 answer
  • Two runners start a race. After 2 seconds, they both have the same velocity. If they both started at the same time, how do their
    10·2 answers
  • Object B has a mass of 8 kg and was lifted at a rate of 3 m/s. What is the kinetic energy of object B?
    5·1 answer
  • Where do asteroids come from? a. There are the remains of a planet between Mars and Jupiter that broke up. b. They are escaped s
    14·1 answer
  • TIME REMAINING
    14·1 answer
  • For problems 6-9, using the formula net Force = Mass• Acceleration calculate the net force on the object.
    7·1 answer
  • Rotational speed refers to the number of complete _____ in a given amount of time.
    7·1 answer
  • 1. Explique con sus palabras por qué el ser humano al nacer es un organismo inacabado, y que influencia ejercen en él las caract
    8·1 answer
  • Hi please zoom in to see it clearly, uh you don’t have to answer them all but it would be nice !!! (no links please) :D
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!