Answer:
The resultant force is F=6i-j-14k while the resultant Moment is about point O (M_o) is 1.3i +3.3 j -0.45k.
Explanation:
As the complete question is not given, the complete question is attached herewith
The coordinates of the points from the Free-body diagram are given as
0=(0,0,0) m
A=(0.15,0,0.3) m
B=(0,-0.25,0.3) m
the position vector of OA is
roa=(0.15-0)i +(0-0)j +(0.3–0)k
= 0.15i +0j +0.3k
the position vector of OB is
rob =(0-0)i +(-0.25 - 0); +(0.3–0)k
= 0i -0.25j +0.3K
Now
The equivalent resultant force is expressed as,
F = F1+ F2
Substitute 6i - 3j -10k for F1, and 2j -4K for F2.
F =6i -3j -10k +2j - 4k
= 6i - 1j -14k
So the resultant force is F=6i-j-14k.
Resultant couple moment at point O is expressed as,
The moment of the resultant force about point O (M_o) is 1.3i +3.3 j -0.45k.
All of the above .........
Answer:
G. 2s
Explanation:
The period of a pendulum is measured in time. Out of the four options, only one of them is measured in time so it must be G.
A period of a pendulum is how long it takes to swing back to it's original position, and this time (2 seconds) is given in the question as well
the speed of sound in water is slower than the speed of air
Answer:
x is approximately 95.495
Explanation:
The given information are;
One lunar month = 30 days
The measured time between the first and third quarters = 14.9 days
Therefore, the angle of rotation for 30 days = 360°
The angle of rotation for 14.9 days = 14.9×360/30 = 178.8°
Therefore, whereby 2·θ = 178.8°
θ = 178.8°/2 = 89.4°
Therefore, given that the angle at the tangent from Sun to the Moon = 90°, we have;
The angle between the line from the Sun to the Moon = 90° - 89.4° = 0.6°
From sine rule, we have;
1/(sin 0.6) = x/(sin 90°)
x = (sin 90°)/(sin 0.6°) ≈ 95.495
x = 95.495.
