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Serhud [2]
3 years ago
10

Destinations humans have traveled in space

Physics
1 answer:
raketka [301]3 years ago
8 0
Yes humans have traveled in space before
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A spherical asteroid of average density would have a mass of 8.7×1013kg if its radius were 2.0 km. 1. If you and your spacesuit
Law Incorporation [45]

1. 0.16 N

The weight of a man on the surface of asteroid is equal to the gravitational force exerted on the man:

F=G\frac{Mm}{r^2}

where

G is the gravitational constant

M=8.7\cdot 10^{13}kg is the mass of the asteroid

m = 100 kg is the mass of the man

r = 2.0 km = 2000 m is the distance of the man from the centre of the asteroid

Substituting, we find

F=(6.67\cdot 10^{-11}m^3 kg^{-1} s^{-2})\frac{(8.7\cdot 10^{13} kg)(110 kg)}{(2000 m)^2}=0.16 N

2. 1.7 m/s

In order to stay in orbit just above the surface of the asteroid (so, at a distance r=2000 m from its centre), the gravitational force must be equal to the centripetal force

m\frac{v^2}{r}=G\frac{Mm}{r^2}

where v is the minimum speed required to stay in orbit.

Re-arranging the equation and solving for v, we find:

v=\sqrt{\frac{GM}{r}}=\sqrt{\frac{(6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2})(8.7\cdot 10^{13} kg)}{2000 m}}=1.7 m/s

3 0
3 years ago
Help<br> A. 12,240<br> B. 6,120
nata0808 [166]

Answer:

A. 12,240.

Explanation:

1,530 times 8.0 = 12,240.

hope this helped :)

3 0
2 years ago
A student walks 10 m North, 6 m South, 7 m West and 4 m East. Find the student's distance AND displacement
BlackZzzverrR [31]

Answer: Distance: 27m Displacement: 7m

Explanation: Distance is total, Displacement is from the start.

Hope this helped!

Mark Brainliest if you feel like it!

5 0
3 years ago
What is the coefficient of friction between the skates and the ice?
natta225 [31]

The coefficient of friction is 0.051

Explanation:

The motion of the skater is a uniformly accelerated motion, therefore we can use the following suvat equation:

v^2 - u^2 = 2as

where:

v = 0 is the final velocity of the skater (he comes to a stop)

u = 10.0 m/s is his initial velocity

a is the acceleration

s=1.0\cdot 10^2 m = 100 m is the distance he travels before stopping

Solving for a, we find the acceleration of the skater:

a=\frac{v^2-u^2}{2s}=\frac{0-10.0^2}{2(100)}=-0.5 m/s^2

We also know that the net force acting on the skater is the force of friction, therefore we can write (Newton's second law of motion):

F= ma = -\mu mg

where

-\mu mg is the force of friction

m is the mass of the skater

\mu is the coefficient of friction

a=-0.5 m/s^2 is the acceleration

g=9.8 m/s^2 is the acceleration of gravity

Solving for \mu, we find the coefficient of friction:

\mu = -\frac{a}{g}=-\frac{-0.5}{9.8}=0.051

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

8 0
3 years ago
Which statement best describes the electrons in this illustration ?
Nonamiya [84]
A. electrons are negatively charged outside nucleus
7 0
3 years ago
Read 2 more answers
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