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2 years ago

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36. Two point charges are separated by 6 cm. The attractive force between them is 20 N. Find the force between them when they ar

e separated by 12 cm. (Why can you solve this problem without knowing the magnitudes of the charges

1 answer:

Alex2 years ago

5 0

Answer:

The force between two charges when they are separated by distance 12 cm is $5N$

Explanation:

Here lets us consider two charges $q_{1}$ and $q_{2}$ .

Let $F_{1}$ be the force between them when they are separated by distance 6 cm

$F_{2}$ be the force between them when distance between them = 12 cm

$F_{1} = \frac{KQ_{1}Q_{2}}{6^{2}}$ =20 N ..................1

$F_{2} = \frac{KQ_{1}Q_{2}}{12^{2}}$ ...................2

Dividing both equations , we get

$\frac{20}{F_{2}} =\frac{12^{2}}{6^{2}}$

$F_{2} = 5N$ .

Here we need not to know the values of charges , since they get cancelled while dividing.

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