A mysterious rocket-propelled object of mass 47.5kg is initially at rest in the middle of the horizontal, frictionless surface o
f an ice-covered lake. Then a force directed east and with magnitudeF(t)= (17.0N/s )t is applied.
How far does the object travel in the first 5.25s after the force is applied?
How far does the object travel in the first 5.25s after the force is applied?
1 answer:
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Answer:
Explanation:
Given:
The area of the house
The height of the house
We need to find the volume of a typical house.
Solution:
We find the volume of the house by multiplying the area of the house and height of the house.
Area and height of the house are known, so we substitute these value in above equation.
Now we convert the unit from feet to meter.
Divide the volume by 3.2808 for
Therefore, the volume of the house is
Answer:
Tension, T = 2038.09 N
Explanation:
Given that,
Frequency of the lowest note on a grand piano, f = 27.5 Hz
Length of the string, l = 2 m
Mass of the string, m = 440 g = 0.44 kg
Length of the vibrating section of the string is, L = 1.75 m
The frequency of the vibrating string in terms of tension is given by :
T = 2038.09 N
So, the tension in the string is 2038.09 N. Hence, this is the required solution.