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Vlad [161]
4 years ago
8

A mysterious rocket-propelled object of mass 47.5kg is initially at rest in the middle of the horizontal, frictionless surface o

f an ice-covered lake. Then a force directed east and with magnitudeF(t)= (17.0N/s )t is applied.
How far does the object travel in the first 5.25s after the force is applied?

Physics
1 answer:
True [87]4 years ago
3 0

Explanation:

Below is an attachment containing the solution.

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A 500-kilogram sports car accelerates uniformly from rest, reaching a speed of 30 meters per second in 6 seconds. During the 6 s
AlekseyPX

Answer:

90 m

Explanation:

Given that

Mass of the car, m = 500 kg

Initial speed of the car, u = 0 m/s

Final speed of the car, v = 30 m/s

Time taken to travel, t = 6 s

average speed v = (30 + 0) / 2 = 15

We are going to be using the most very basic equations to solve this.

speed can be defined as the ratio of distance with respect to time.

v = d/t, Where

v = speed.

d = distance travelled and

t = time taken

if we invert this, we can get that

d = v.t

distance is multiplication of speed and time. We will be using the average speed we calculated above, so

Distance travelled in 6 s,

d = 15 * 6

d = 90 m.

therefore, the distance travelled by the car in this 6 s is 90 m

4 0
3 years ago
Which three types of electromagnetic waves carry most of the Sun's energy that strikes Earth?
pshichka [43]

Answer:

A.

Explanation:

3 0
3 years ago
How many meters are in a gigameter?
gladu [14]

Answer:

1 gigameter = 1e+9 meter

7 0
4 years ago
Un movil aumenta su velocidad de 10m/s a 20m/s acelerando uniformemente a razon de 5m/s2 ¿que distancia logro en dicha operacion
Kruka [31]

v₀ = initial velocity of the mobile = 10 m/s

v = final velocity of the mobile = 20 m/s

a = acceleration of the mobile = 5 m/s²

d = distance traveled during this operation = ?

Using the kinematics equation

v² = v²₀ + 2 a d

inserting the above values in the equation

20² = 10² + 2 (5) d

400 = 100 + 10 d

subtracting 100 both side

400 - 100 = 100 - 100 + 10 d

300 = 10 d

dividing both side by 10

300/10 = 10 d/10

d = 30 m

hence mobile travels 30 m.

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1) A rock thrown horizontally from the top of a
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Dx = 20m
V1 = 10m/s
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(delta-t) = 2sec
dy = 19.6m 
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3 years ago
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