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3 years ago

Independent practice

Physics

1 answer:

coldgirl [10]3 years ago

4 0

Explanation:

formula: <u>Mass</u>

Density x volume

2a) m=10kg v=0.3m³

10÷0.3=33.3 kg/m

2b) m = 160 kg V=0.1m³

160÷0.1=1600 kg/m

2c) m = 220 kg V = 0.02m³

220÷0.02=11000 kg/m

A wooden post has a volume of 0.025m³ and a mass of 20kg. Calculate its density in kg/m.

density = volume ÷ mass

20÷ 0.025=800 kg/m

Challenge: A rectangular concrete slab is 0.80m long, 0.60 m wide and 0.04m thick. Calculate its volume in m³.

Formula : Length x width x height = Volume

0.80 x 0.60 x 0.04 = 0.0192m³

B) The mass of the concrete slab is 180 kg. Calculate its density in kg/m.

density = volume ÷ mass

180 ÷ 0.0192 = 9375 kg/m

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A mass is undergoing simple harmonic motion. When its displacement is 0, it is at its equilibrium position. At that moment, its

likoan [24]

Answer:

When X = 0

Speed = maximum V (max) = ω A

Acceleration = zero a(max) = - ω^2 A

From x = A sin ω t sin = 0 so displacement = zero

V = ω A cos ω t cos = 1 and speed = maximum

a = - A ω^2 sin ω t sin = 0 and acceleration = zero

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2 years ago

What is the coefficient of friction between the skates and the ice?

natta225 [31]

The coefficient of friction is 0.051

Explanation:

The motion of the skater is a uniformly accelerated motion, therefore we can use the following suvat equation:

$v^2 - u^2 = 2as$

where:

v = 0 is the final velocity of the skater (he comes to a stop)

u = 10.0 m/s is his initial velocity

a is the acceleration

$s=1.0\cdot 10^2 m = 100 m$ is the distance he travels before stopping

Solving for a, we find the acceleration of the skater:

$a=\frac{v^2-u^2}{2s}=\frac{0-10.0^2}{2(100)}=-0.5 m/s^2$

We also know that the net force acting on the skater is the force of friction, therefore we can write (Newton's second law of motion):

$F= ma = -\mu mg$

where

$-\mu mg$ is the force of friction

m is the mass of the skater

$\mu$ is the coefficient of friction

$a=-0.5 m/s^2$ is the acceleration

$g=9.8 m/s^2$ is the acceleration of gravity

Solving for $\mu$ , we find the coefficient of friction:

$\mu = -\frac{a}{g}=-\frac{-0.5}{9.8}=0.051$

Learn more about friction:

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3 years ago

Physics Circuit, need a walkthrough

QveST [7]

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3 years ago

If the average gauge pressure in the vein is 12200 Pa, what must be the minimum height of the bag in order to infuse glucose int

Amanda [17]

Answer:

h = 1.22 m

Explanation:

Given:

Pressure in the vein = 12200 Pa

Specific gravity of the liquid = 1.02

now,

the pressure due to a fluid is given as:

P = pgh

where,

P is the pressure,

ρ is the density of fluid = specific gravity x density of water = 1.02 x 1000 kg/m³

ρ = 1020 kg/m³

g is the acceleration due to the gravity = 9.81m/s²

h is the height

thus,

h = P/pg = $\frac{12200}{1020\times 9.8}=1.22 m$

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3 years ago

What is the action force and the reaction force when you sit down on a chair

Licemer1 [7]

The action force is when you are putting your weight on the chair when you are sitting down. the reaction force is the force exerted by the chair that pushes up on your body and is equal to your weight.

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3 years ago