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tensa zangetsu [6.8K]
3 years ago
10

What is the most power in watts the ear can receive before the listener feels pain?

Physics
1 answer:
svp [43]3 years ago
5 0
The softest sound a human ear can hear is at 0dB. Sounds above 130dB causes pain.
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Question 1 of 20
ad-work [718]

Answer

D. move a small magnet back and forth within a section of the coiled wire.

Explanation:

i put that for the test and i got it right

8 0
3 years ago
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20 Points available for physics help
Sonja [21]
The second one is correct not sure about the first one sorry
8 0
3 years ago
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use the pendulum equation to calcuate the period of a 1.50 pendulum. Remeber that the vaule of "g" is 9.81 m/s² please help ​
kati45 [8]

Answer:

L = 3.51

Explanation:

Pendulum equation is T = 2pi\sqrt{L/9.81}

T = 1.5 and we are solving for L

1.5=2\pi \sqrt{L/9.81}

square both sides to get 2.25 = 2\pi ( L/9.81)

multiply both sides by 9.81 then divide by 2 and 3.14 as a substitue for pi. The answer should be about 3.51 in length

L = 3.51

If this helps, mark me brainliest pls

3 0
3 years ago
These are nontoxic, nonflammable chemicals containing atoms of carbon, chlorine, and fluorine that have created a hole in the oz
Grace [21]
<span>The correct answer is: Chlorofluorocarbons (CFCs)

Explanation:
In simple words, CFCs are the chemical compounds made up of the following three elements:
1. Carbon
2. Chlorine
3. Fluorine

When CFCs compounds reach the upper atmosphere, the ultraviolet rays coming from the Sun break those compounds into individual elements, which then react with one of the oxygen atom of the ozone (O3) to form new compounds like chlorine monoxides. That way the ozone molecules get destroyed, resulting into the ozone depletion. Hence, the correct answer is Chlorofluorocarbons (CFCs).</span>
6 0
4 years ago
Read 2 more answers
3.50 µf capacitor has a charge with a magnitude of 4.50 µC on each parallel plate. Find the potential difference between the pla
n200080 [17]

Answer:

b) 1.29 V

Explanation:

Potential Difference: This is the work done when one coulomb of charge moves from one point to another in an electric field

The expression for the potential difference is

Q = CV .................... Equation 1

Where Q = amount of charge, C = Capacitance of the capacitor, V = potential difference.

Making V the subject of the equation,

V = Q/C................. Equation 2

Given: Q = 4.5  µC = 4.5×10⁻⁶ C, C = 3.5  µF = 3.5×10⁻⁶ F

Substituting into equation 2

V = 4.5×10⁻⁶ /3.5×10⁻⁶

V = 1.2857 V

V ≈ 1.29 V.

Hence the right option is  b) 1.29 V

8 0
3 years ago
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