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3 years ago

Give two possible sets of four quantum numbers for the electron in hydrogen when it is in its lowest energy state.

Chemistry

1 answer:

konstantin123 [22]3 years ago

4 0

Answer:

Explanation:

The electron in the lowest energy state will be found in 1 s energy level.

set of 4 possible quantum numbers

Principal quantum no : n = 1 ,

Azimuthal quantum no l = 0

Magnetic quantum no m = 0

Spin quantum no s = + 1/2

set of other quantum nos

Principal quantum no : n = 1 ,

Azimuthal quantum no l = 0

Magnetic quantum no m = 0

Spin quantum no s = - 1/2

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A student has a 2.19 L bottle that contains a mixture of O 2 , N 2 , and CO 2 with a total pressure of 5.57 bar at 298 K . She k

Sergeeva-Olga [200]

<u>Answer:</u> The partial pressure of oxygen gas is 2.76 bar

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 5.57 bar

V = Volume of the gas = 2.19 L

T = Temperature of the gas = 298 K

R = Gas constant = $0.0831\text{ L bar }mol^{-1}K^{-1}$

n = Total number of moles = ?

Putting values in above equation, we get:

$5.57bar\times 2.19L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{5.57\times 2.19}{0.0831\times 298}=0.493mol$

To calculate the mole fraction of carbon dioxide, we use the equation given by Raoult's law, which is:

$p_{A}=p_T\times \chi_{A}$ ........(1)

where,

$p_A$ = partial pressure of carbon dioxide = 0.318 bar

$p_T$ = total pressure = 5.57 bar

$\chi_A$ = mole fraction of carbon dioxide = ?

Putting values in above equation, we get:

$0.318bar=5.57bar\times \chi_{CO_2}\\\\\chi_{CO_2}=\frac{0.381}{5.57}=0.0571$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

We are given:

Moles of nitrogen gas = 0.221 moles

Mole fraction of nitrogen gas, $\chi_{N_2}=\frac{0.221}{0.493}=0.448$

Calculating the partial pressure of oxygen gas by using equation 1, we get:

Mole fraction of oxygen gas = (1 - 0.0571 - 0.448) = 0.4949

Total pressure of the system = 5.57 bar

Putting values in equation 1, we get:

$p_{O_2}=5.57bar\times 0.4949\\\\p_{O_2}=2.76bar$

Hence, the partial pressure of oxygen gas is 2.76 bar

6 0

4 years ago

In just thomsons experiments with electricity he showed that an electrical current can be

katen-ka-za [31]

In Thomson's experiment, he showed that an electrical current can be made to flow from a positive site to a negative site.

6 0

3 years ago

Read 2 more answers

Explain why the C―Ha bond is much more acidic than the C―Hb bond in pentan-2-one. Select the single best answer. 253 Ha is less

mafiozo [28]

Answer:

Ha is more acidic than Hb because loss of Ha forms a resonance-stabilized conjugate base.

Explanation:

The carbon atom that is next to the carbonyl group in pentan-2-one is known as the alpha carbon atom, this carbon atom bears the Ha, the alpha hydrogen atoms.

Ha is more acidic than Hb because, loss of Ha leads to the formation of a resonance stabilized enolate ion. This resonance stabilization of the ion formed makes loss of Ha an easier process than loss of Hb, hence the answer above.

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4 years ago

128.3 grams of methane (CH4) is equal to how many moles of methane

Neko [114]

About 8.0 moles of methane.Number of moles = MassMolar mass.

And thus we get the quotient:

128.3⋅g16.04⋅g⋅mol−1=8.0⋅moles of methane.

Note that the expression is dimensionally consistent, we wanted an answer in moles, and the quotients gives, 1mol−1=11mol=mol as required.

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3 years ago

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What is the volume of 18.9 g of a liquid that has a density of 0.956 g/ml

Alex_Xolod [135]

The volume is 19.76987448 by taking the known variables mass=18.9g and density=0.956g/ml
To get volume you divide the mass by the density which gives you about
19.77 ml in volume

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3 years ago