Explanation:
The first equation of motion in kinematics is given by :
.....(1)
u is initial speed
a is acceleration
v is final speed
t is time
Equation (1) is valid when the object is moving with constant acceleration. This equation gives relation between velocity and time.
We don't know how many of ANY color are in the bag right now, so there's no way to calculate an answer.
What Tom has to do is make sure that the number of marbles that are NOT blue is NINE TIMES the number of blue ones in the bag.
<em><u>One</u></em><em><u> </u></em><em><u>newton</u></em><em><u> </u></em><em><u>force</u></em><em> </em><em>is</em><em> </em><em>defined as t</em><em>h</em><em>e</em><em> </em><em>force</em><em> </em><em>that</em><em> </em><em>is</em><em> necessary to provide a mass of one kilogram with an acceleration of one metre per second per second. One newton is equal to a force of 100,000 dynes in the centimetre-gram-second (CGS) system, or a force of about 0.2248 pound </em><em>i</em><em>n</em><em> </em><em>the</em><em> </em><em>f</em><em>o</em><em>o</em><em>t</em><em>-</em><em>p</em><em>o</em><em>u</em><em>n</em><em>d</em><em>-</em><em> </em><em>s</em><em>e</em><em>c</em><em>o</em><em>n</em><em>d</em><em> </em><em>system</em><em>.</em>
Let
be the average acceleration over the first 2.46 seconds, and
the average acceleration over the next 6.79 seconds.
At the start, the car has velocity 30.0 m/s, and at the end of the total 9.25 second interval it has velocity 15.2 m/s. Let
be the velocity of the car after the first 2.46 seconds.
By definition of average acceleration, we have


and we're also told that

(or possibly the other way around; I'll consider that case later). We can solve for
in the ratio equation and substitute it into the first average acceleration equation, and in turn we end up with an equation independent of the accelerations:


Now we can solve for
. We find that

In the case that the ratio of accelerations is actually

we would instead have

in which case we would get a velocity of
