A 4 kg kitten is sliding at 12 m/s on a horizontal frictionless surface. A constant force is applied that slows it with an accel

Question

Sergeu [11.5K]

4 years ago

14

A 4 kg kitten is sliding at 12 m/s on a horizontal frictionless surface. A constant force is applied that slows it with an accel

eration of 3 m/s/s. How much work must this force do to stop the kitten

Physics

1 answer:

Liono4ka [1.6K] · Answer 1 · 2021-12-23T05:45:56+03:00

Answer:

288 Joules

Explanation:

Work= delta kinetic energy. To find the work required to stop the kitten, you have to find the delta kinetic energy between when the kitten is moving and when it is stopped. Since it is not moving when it's stopped, it has no kinetic energy. So to find the work, just find the kinetic energy of the kitten moving at 12m/s.

KE=1/2((m)(v^2)), therefore

delta KE=(1/2)*((4kg)*((12m/s)^2))-0