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Sladkaya [172]
3 years ago
13

What number on this diagram refers to the tick marks for the dependent variable?

Physics
1 answer:
givi [52]3 years ago
4 0

Answer:

I'm pretty sure it's 3.

Explanation:

Because if you look at your options the only that would be relevant to tick marks would be either 4 or 3. And it said in the question that we're looking for the one for the dependent variable. And the dependent variable is on the Y- Axis and the 3 is the tick marks for the y-axis. So your answer is 3.

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MIDDLE SCHOOL SCIENCE- <br> Please help, I will give brainliest to best answer.
tatyana61 [14]

Answer:

1.) Waves carry energy through empty space or through a medium without transporting matter. While all waves can transmit energy through a medium, certain waves can also transmit energy through empty space. ... When waves travel through a medium, the particles of the medium are not carried along with the wave.

2.) Mechanical Waves are waves which propagate through a material medium (solid, liquid, or gas) at a wave speed which depends on the elastic and inertial properties of that medium. There are two basic types of wave motion for mechanical waves: longitudinal waves and transverse waves. Longitudinal waves vibrating in the direction of propagation while Transverse waves vibrate at right angles to the direction of its propagation.

3.) They can carry a little energy or a lot of energy. They can be transverse or longitudinal. However, all waves have common properties—amplitude, wavelength, frequency, and speed. Amplitude describes how far the medium in a wave moves.

I hope this helps!

5 0
2 years ago
Cousin Throckmorton is playing with the clothesline. One end of the clothesline is attached to a vertical post. Throcky holds th
Oksi-84 [34.3K]

Answer:

The  frequencies are  f_n  =  n (0.875 )

Explanation:

From the question we are told that

   The speed of the wave is  v  =  0.700 \  m/s

   The  length of vibrating  clothesline is  L  =  40.0 \  cm = 0.4 \ m

Generally the fundamental frequency is  mathematically represented as

        f =  \frac{v}{2 L  }

=>     f =  \frac{ 0.700 }{2 *  0.4   }

=>     f =  0.875 \  Hz

Now  this other frequencies of vibration experience by the clotheslines are know as harmonics and they are obtained by integer multiple of  the fundamental frequency

So  

   The  frequencies are mathematically represented as

       f_n  =  n  * f

=>     f_n  =  n (0.875 )

Where  n  =  1, 2, 3 ....

       

3 0
3 years ago
A ball is launched from ground level at 20 m/s at an angle of 40° above the
DedPeter [7]

(a) The ball's height <em>y</em> at time <em>t</em> is given by

<em>y</em> = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve <em>y</em> = 0 for <em>t</em> :

0 = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²

0 = <em>t</em> ((20 m/s) sin(40º) - 1/2 <em>g t</em> )

<em>t</em> = 0   or   (20 m/s) sin(40º) - 1/2 <em>g t</em> = 0

The first time refers to where the ball is initially launched, so we omit that solution.

(20 m/s) sin(40º) = 1/2 <em>g t</em>

<em>t</em> = (40 m/s) sin(40º) / <em>g</em>

<em>t</em> ≈ 2.6 s

(b) At its maximum height, the ball has zero vertical velocity. In the vertical direction, the ball is in free fall and only subject to the downward acceleration <em>g</em>. So

0² - ((20 m/s) sin(40º))² = 2 (-<em>g</em>) <em>y</em>

where <em>y</em> in this equation refers to the maximum height of the ball. Solve for <em>y</em> :

<em>y</em> = ((20 m/s) sin(40º))² / (2<em>g</em>)

<em>y</em> ≈ 8.4 m

8 0
2 years ago
¿Cuál es el lado positivo sobre el auge de la <br><br>industrialización<br>​
Nesterboy [21]

Answer:

El lado positivo que tuvo el auge de la industrialización es principalmente que: Permitió el desarrollo económico de una gran cantidad de países. Marco un nuevo estilo de vida con mayor índice de globalización y producción. Creó una gran cantidad de fuentes de empleo.

Explanation:

3 0
3 years ago
Susan, driving north at 53 mphmph , and Shawn, driving east at 63 mphmph , are approaching an intersection. Part A What is Shawn
mafiozo [28]

Answer:

Shawn's speed relative to Susan's speed = 10 mph

Resultant velocity = 82.32 mph

Explanation:

The given data :-

i) Susan driving in north and speed of Susan is ( v₁ ) = 53 mph.

ii) Shawn driving in east and speed of Shawn is ( v₂ ) = 63 mph.

iii) The speed of both Susan and Shawn is relative to earth.

iv) The angle between Susan in north and Shawn in east is 90°.

We have to find Shawn's speed relative to Susan's speed.

v₂₁ = v₂ - v₁   = 63 - 53 = 10 mph

Resultant velocity,

v = \sqrt{v_{2} ^{2}+ v_{1} ^{2}  }  =\sqrt{63^{2} +53^{2} }

v = 82.32 mph

5 0
3 years ago
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