Answer:
B) 0.59 M NaCl.
Explanation:
- It is known that the no. of millimoles of NaCl before dilution = the no. of millimoles of NaCl after dilution.
∵ (MV) before dilution = (MV) after dilution.
<em>∴ M after dilution = (MV) before dilution / V after dilution </em>= (3.2 M)(25.0 mL)/(135.0 mL) = <em>0.5926 M ≅ 0.59 M.</em>
HNO₃(aq) + NaOH(aq) → NaNO₃(aq) + H₂O(l)
H⁺ + NO₃⁻ + Na⁺ + OH⁻ → Na⁺ + NO₃⁻ + H₂O
H⁺ + OH⁻ → H₂O (the net ionic equation)
The answer is Na+ Cl- and F+. Hope this helps!!!
Answer:
Being a weak acid and a strong base, where it is diluted in a neutral medium such as water, the basic medium predominates, almost alkaline pH.
Explanation:
The acidity of the solution, being weak, means that its pH is not so low, therefore it will be easier to reach the values of 7 or 7 where alkalinity or basity is indicated.
Answer: between 6.5 and 8.5
Explanation:
As shown in my science book it appears in the ph scale
