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BigorU [14]
3 years ago
9

A helium balloon ride lifts up passengers in a basket. Assume the density of air is 1.28 kg/m3 and the density of helium in the

balloon is 0.18 kg/m3. The radius of the balloon (when filled) is R = 4.5 m. The total mass of the empty balloon and basket is mb = 123 kg and the total volume is Vb = 0.068 m3. Assume the average person that gets into the balloon has a mass mp = 74 kg and volume Vp = 0.077 m3.What is the volume of helium in the balloon when fully inflated?
Physics
1 answer:
max2010maxim [7]3 years ago
3 0

Answer:

V = 381.70 m³

Explanation:

ρ air = 1.28 kg / m³

ρ helium = 0.18 kg / m³

R = 4.5 m

Vb = 0.068 m³

mb = 123 kg

To determine the volume of helium in the balloon when fully inflated

V = 4 / 3 π * R ³

V = 4 * π / 3 ( 4.5 m )³

V = 381.70 m³

To determine the mass total

m = ρ helium * V

m = 0.18 kg / m³  * 381.70  m³

m = 68.70 kg

mt = ( 68.70 + 123 )kg

mt = 191.70 kg

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Answer:

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3 years ago
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Making acceleration the subject of formula, we have;

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In this scenario, the acceleration of a baseball after it is hit by a bat depends on the mass of the ball and the net force on the ball. Thus, this example best illustrates Newton's second law of motion.

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\frac{DT}{dt} = <em>k</em>(T − 70), T(0) = 300

Solving the equation, we get

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In [T-70]= <em>kt </em>+C_{1}

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Finding he value for C_{2} using the initial value of T (0)= 300, therefore we get:

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Finding the value for <em>k </em>using T (3)  = 200, therefore we get

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Answer:

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Explanation:

See attachment below.

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