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balandron [24]
3 years ago
9

Several kinds of bears are found on Earth. Most bears are brown or black, but one type of bear, the polar bear, is white. What p

rocess led to this difference in fur color? Explain your answer.
Chemistry
2 answers:
KengaRu [80]3 years ago
8 0

Sample Response: <em>The process that lead to this difference in fur color is called "natural selection." Polar Bears live in the arctic, where there is snow all around. In this kind of environment, white bears blend in well with their surroundings while brown and black bears stand out. This means that brown and black bears would be easier to spot as prey, and would not survive in an arctic environment. Since white bears are more adapted to the environment, they would survive and reproduce, creating a large population of white bears.</em>

jeka943 years ago
7 0

This is called adaptation. An example would be a polar bear with white fur. They have this to be more efficent hunters, as they use it as a type of camouflage in order to sneak up on prey. Brown bear use this in the same way but their environment requires them to be brown in order to blend in beter with trees. So basicly adaptation

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2 years ago
To evaluate R. the volume of a gas measured in the temperature of the gas is measured in<br> while
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6 0
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Read 2 more answers
) Given the following balanced equation, determine the rate of reaction with respect to [O2]. If the rate of formation of O2is 7
Travka [436]

Answer:

Rate of the reaction is 0.2593 M/s

-0.5186 M/s is the rate of the loss of ozone.

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The rate of the reaction is defined as change in any one of the concentration of reactant or product per unit time.

2O_3\rightleftharpoons 3O_2

Rate of formation of oxygen : 7.78\times 10^{-1} M/s

Rate of the reaction(R) =\frac{-1}{2}\frac{d[O_3]}{dt}=\frac{1}{3}\frac{d[O_2]}{dt}

R=\frac{1}{3}\frac{d[O_2]}{dt}

Rate of formation of oxygen=3 × (R)

7.78\times 10^{-1} M/s=3\times R

Rate of the reaction(R): 0.2593 M/s

Rate of the reaction is 0.2593 M/s

Rate of disappearance of the ozone:

R=-\frac{1}{2}\frac{d[O_3]}{dt}

\frac{d[O_3]}{dt}=-2\times R=-2\times 0.2593\times M/s=-0.5186M/s

-0.5186 M/s is the rate of the loss of ozone.

6 0
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