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anastassius [24]
2 years ago
12

Cliffs may be affected by weathering. Describe ONE  effect of weathering on a cliff .

Chemistry
2 answers:
Kisachek [45]2 years ago
6 0
If it rains too much it could affect the cliff because rain has acid in it which could eat up the cliff. If the cliff was limestone or a sedimentary rock it would eat up the cliff quicker.
Anni [7]2 years ago
4 0
Well if too much weathering occurs, it might break off parts of the cliff and be dangerous to humans, or animals. 
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2.
schepotkina [342]

Answer:

b. 6.02 x 1023 molecules

Explanation:

The formula mass of ammonia is 14 + 1 × 3 = 17.

The number of moles in 27.6g ammonia is 27.6 ÷ 17 = 1.62 mol.

A mole is 6.02 × 10²³, so the number of hydrogen atoms in a 1.62 moles of ammonia is 1.62 × 6.02 × 10²³ × 3 = 2.93 × 10² atoms.

3 0
2 years ago
Which conversion factor do you use first to calculate the number of grams of CO 2 produced by the reaction of 50.6 g of CH 4 wit
Brilliant_brown [7]

Answer:

Thus, first conversion of mass of methane into moles by dividing it with 16.04 g/mol

Mass =  138.63 g

Explanation:

The balanced chemical reaction is shown below:-

CH_4+2O_2\rightarrow CO_2+2H_2O

Firstly the moles of methane gas reacted must be calculate as:-

Given, mass of methane = 50.6 g

Molar mass of methane gas = 16.04 g/mol

The formula for the calculation of moles is:-

Moles=\frac{Mass\ taken}{Molar\ mass}=\frac{50.6}{16.04}\ mol=3.15\ mol

Thus, from the reaction stoichiometry,

1 mole of methane produces 1 mole of carbon dioxide

Also,

3.15 mole of methane produces 3.15 mole of carbon dioxide

Moles of CO_2 = 3.15 mole

Molar mass of CO_2 = 44.01 g/mol

Mass = Moles*Molar mass = 3.15\times 44.01 g = 138.63 g

3 0
2 years ago
Water is formed when two hydrogen atoms bond to an oxygen atom.
dem82 [27]
They are two different elements, C. Elements
6 0
3 years ago
What is the energy required to go from liquid to gas called answers?
Tresset [83]
Answer:
            <span>The energy required to go from liquid to gas is called as Latent Heat of Vaporization.

Explanation:
                   The process of conversion of liquid into gas phase is known as vaporization while the conversion of gas into liquid state is called as condensation. The liquid having stronger intermolecular forces than gases require some energy to break those interactions hence, the heat provided to break these interactions and convert it into gas phase is called as heat of vaporization. Remember, heat of vaporization and heat of condensation are same for a given substance but with different signs.

Example:

Heat of Vaporization of Water  =  40.65 kJ/mol

Heat of Condensation of Water  =  - 40.65 Kj/mol</span>
5 0
3 years ago
At a certain temperature, 0.760 mol SO3 is placed in a 1.50 L container. 2SO3(g) = 2SO2(g) + O2(g)At equilibrium, 0.130 mol O2 i
olganol [36]

Answer:

K_c=0.0867

Explanation:

Moles of SO₃ = 0.760 mol

Volume = 1.50 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.760}{1.50\ L}

[SO₃] = 0.5067 M

Considering the ICE table for the equilibrium as:

\begin{matrix} & 2SO_3_{(g)} & \rightleftharpoons & 2SO_2_{(g)} & + & O_2_{(g)}\\At\ time, t = 0 & 0.5067 &&0&&0 \\ At\ time, t=t_{eq} & -2x &&2x&&x \\----------------&-----&-&-----&-&-----\\Concentration\ at\ equilibrium:- &0.5067-2x&&2x&&x\end{matrix}

Given:    

Equilibrium concentration of  O₂ = 0.130 mol

Volume = 1.50 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.130}{1.50\ L}

[O₂] = x = 0.0867 M

[SO₂] = 2x = 0.1733 M

[SO₃] = 0.5067-2x = 0.3334 M

The expression for the equilibrium constant is:

K_c=\frac {[SO_2]^2[O_2]}{[SO_3]^2}  

K_c=\frac{(0.3334)^2\times 0.0867}{(0.3334)^2}

K_c=0.0867

5 0
3 years ago
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