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3 years ago

Cliffs may be affected by weathering. Describe ONE effect of weathering on a cliff .

2 answers:

6 0

If it rains too much it could affect the cliff because rain has acid in it which could eat up the cliff. If the cliff was limestone or a sedimentary rock it would eat up the cliff quicker.

Anni [7]3 years ago

4 0

Well if too much weathering occurs, it might break off parts of the cliff and be dangerous to humans, or animals.

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The motion of a toy truck was investigated. The total distance covered vs. time was recorded in the table.

DIA [1.3K]

Answer:

Where the chart pls I can answer

Explanation:

3 0

3 years ago

Suppose you need to heat food. What wave type from the electromagnetic spectrum could you use?

N76 [4]

Answer:

Microwave radiation

Explanation:

This radiation is the one used in microwaves.

8 0

3 years ago

Read 2 more answers

Formaldehyde is a carcinogenic volatile organic compound with a permissible exposure level of 0.75 ppm. At this level, how many

Flauer [41]

Answer : The amount of formaldehyde permissible are, $5.4\times 10^{-6}g$

Explanation : Given,

Density of air = $1.2kg/m^3=1.2g/L$ $(1kg/m^3=1g/L)$

First we have to calculate the mass of air.

$\text{Mass of air}=\text{Density of air}\times \text{Volume of air}$

$\text{Mass of air}=1.2g/L\times 6.0L$

$\text{Mass of air}=7.2g$

Now we have to calculate the amount of formaldehyde.

Permissible exposure level of formaldehyde = 0.75 ppm = $\frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}$

Amount of formaldehyde in 7.2 g of formaldehyde = $7.2g\times \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}$

Amount of formaldehyde in 7.2 g of formaldehyde = $5.4\times 10^{-6}g$

Thus, the amount of formaldehyde permissible are, $5.4\times 10^{-6}g$

8 0

3 years ago

In an aqueous solution of a certain acid the acid is 4.4% dissociated and the pH is 3.03. Calculate the acid dissociation consta

NeX [460]

Answer:

4.1x10⁻⁵

Explanation:

The dissociation of an acid is a reversible reaction, and, because of that, it has an equilibrium constant, Ka. For a generic acid (HA), the dissociation happens by:

HA ⇄ H⁺ + A⁻

So, if x moles of the acid dissociates, x moles of H⁺ and x moles of A⁻ is formed. the percent of dissociation of the acid is:

% = (dissociated/total)*100%

4.4% = (x/[HA])*100%

But x = [A⁻], so:

[A⁻]/[HA] = 0.044

The pH of the acid can be calcualted by the Handersson-Halsebach equation:

pH = pKa + log[A⁻]/[HA]

3.03 = pKa + log 0.044

pKa = 3.03 - log 0.044

pKa = 4.39

pKa = -logKa

logKa = -pKa

Ka = $10^{-pKa}$

Ka = $10^{-4.39}$

Ka = 4.1x10⁻⁵

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3 years ago

Alcohol begins to affect your brain _______

zvonat [6]

Alcohol begins to affect your brain cells

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3 years ago