Answer:
b. 6.02 x 1023 molecules
Explanation:
The formula mass of ammonia is 14 + 1 × 3 = 17.
The number of moles in 27.6g ammonia is 27.6 ÷ 17 = 1.62 mol.
A mole is 6.02 × 10²³, so the number of hydrogen atoms in a 1.62 moles of ammonia is 1.62 × 6.02 × 10²³ × 3 = 2.93 × 10² atoms.
Answer:
Thus, first conversion of mass of methane into moles by dividing it with 16.04 g/mol
Mass = 138.63 g
Explanation:
The balanced chemical reaction is shown below:-

Firstly the moles of methane gas reacted must be calculate as:-
Given, mass of methane = 50.6 g
Molar mass of methane gas = 16.04 g/mol
The formula for the calculation of moles is:-

Thus, from the reaction stoichiometry,
1 mole of methane produces 1 mole of carbon dioxide
Also,
3.15 mole of methane produces 3.15 mole of carbon dioxide
Moles of
= 3.15 mole
Molar mass of
= 44.01 g/mol
Mass = Moles*Molar mass =
g = 138.63 g
They are two different elements, C. Elements
Answer:
<span>The energy required to go from liquid to gas is called as Latent Heat of Vaporization.
Explanation:
The process of conversion of liquid into gas phase is known as vaporization while the conversion of gas into liquid state is called as condensation. The liquid having stronger intermolecular forces than gases require some energy to break those interactions hence, the heat provided to break these interactions and convert it into gas phase is called as heat of vaporization. Remember, heat of vaporization and heat of condensation are same for a given substance but with different signs.
Example:
Heat of Vaporization of Water = 40.65 kJ/mol
Heat of Condensation of Water = - 40.65 Kj/mol</span>
Answer:

Explanation:
Moles of SO₃ = 0.760 mol
Volume = 1.50 L


[SO₃] = 0.5067 M
Considering the ICE table for the equilibrium as:

Given:
Equilibrium concentration of O₂ = 0.130 mol
Volume = 1.50 L


[O₂] = x = 0.0867 M
[SO₂] = 2x = 0.1733 M
[SO₃] = 0.5067-2x = 0.3334 M
The expression for the equilibrium constant is:
