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ioda
4 years ago
9

When 3.2g of ammonium chloride is dissolved in 75g of water, the temperature of the solution decreases from 22.8 C to 20.1 C. Wh

at is the energy of dissolution of NH4Cl per mole?
Chemistry
2 answers:
ser-zykov [4K]4 years ago
7 0
Dissolving NH4Cl in H2O is an endothermic solution process. You measure how much it cools the solution by the temperature of the H2O. 
<span>q = mass H2O x specific heat H2O x (Tfinal-Tinitial) </span>
<span>The q you measure is for 3.2g/53.4g or q/0.0599 mol. You want to convert that to q/1 mol. </span>
kondor19780726 [428]4 years ago
3 0

14.8 kJ/mol ...........

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What product of an acid base reaction is an ionic compound apex?
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3 years ago
Read 2 more answers
PLEASE SOMEONE HELP ME WITH THIS!
Bad White [126]

Answer:

1) 1.202 L , 2) 1.291 dg , 3) 204.877  and 4) 1.04x10^{3\\}

Explanation:

You need to review about conversion factors and how to use them in the correct order. You can cancel the units and get the ones that you need if you use the appropriate conversion factors, remember is a number that you can use to multiply or divide.

For your exercise:

1) The conversion factor is: 1 L = 1000 mL

You will need to divide by 1000 mL to obtain liters L

1202.57120 mL x  \frac{1 L}{1000 mL} = 1.202 L

2) The conversion factor is: 1 g = 10 dg

0.1290743 g x \frac{10 dg}{ 1 g} = 1.291 dg

For the next exercises, you need to follow some rules:

1.  All numbers  that are different from Zero (non-zero digits) are significant figures.

2.The Zeros between non-zeros digits (Imbedded zeros) always are significant, 2007.

3. If you want to be specific and want some zeros to be significant you need to add a decimal point. For example 500. or 500.0

4. Leading zeros (to the left) are not significant.

5. Trailing zeros (zeros to the right) in a whole number without decimal point are not significant.

3) 843.062  - 638.1848  = 204.8772

Now if we round to 6 significant figures we get 204.877

4)123.0 x 8.43 = 1036.89

Now we round to 3 significant figures because 8.43 has the least significant figures.  

1.04x10^{3}

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3 years ago
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A. As pressure on the gas increases, the volume and temperature will both decrease

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