Compared to the particles in a gas, the particles in a solid move

What types of atoms release nuclear radiation

djyliett [7]

Isotopes of elements where the nucleas is unstable generally release nuclear radiation. So unstable atoms

4 0

3 years ago

Specific gravity of a vegetable oil is 0.85. What is its density?

elena-s [515]

I think its density is 850kg/m^3

6 0

3 years ago

A plasma membrane and a cell wall _____.

klemol [59]

<h3>Answer;</h3>

D. Have different structures and different functions

A plasma membrane and a cell wall have different structures and different functions.

<h3>Explanation;</h3>

Plasma membrane is a structure that is found in both animal cell and plants cells. It is made up of a bi-layer consisting of lipid and proteins. Plasma membrane are semi-permeable which means the allow selective movement of materials in and out of the cell.

Cell wall, on the other hand is a structure that is found on plant cells and lacks in animal cell. It contains cellulose in its structure which enables it to be rigid and enhances it protect the cell from mechanical damage from harsh conditions such as pressure in the outside environment.

5 0

3 years ago

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Which type of muscle is found only in the heart?

Mama L [17]

Answer:

b. Cardiac muscles.

Explanation:

These muscles are very thick in order to pump oxygenated blood to all body parts.

$.$

4 0

3 years ago

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Automobile battery acid is 38% H2SO4 and has a destiny of 1.29g/ml. Calculate the molality and the molarity of this solution.

baherus [9]

Answer:

$M=5.0M\\\\m=6.2m$

Explanation:

Hello,

In this case, 38 % is commonly a by mass concentration, meaning that we have 38 grams of solute (sulfuric acid) per 100 grams of solution (water+sulfuric acid):

$38\%=\frac{m_{H_2SO_4}}{m_{H_2SO_4}+m_{H_2O}}$

Hence, we compute the moles of sulfuric acid in 38 grams by using its molar mass (98 g/mol):

$n_{H_2SO_4}=38g*\frac{1mol}{98g}=0.39mol H_2SO_4$

Next, the volume of the solution in litres by using the density of the solution:

$V_{solution}=100g*\frac{1mL}{1.29g}*\frac{1L}{1000mL} =0.0775L$

This is done since the molarity is defined as the ratio of the moles of the solute to the volume of the solution in litres, thus we have:

$M=\frac{n}{V}=\frac{0.38mol}{0.0775L}=5.0M$

On the other hand, the molality is defined as the ratio of the moles of the solute to the mass of the solvent in kilograms, thus, we compute the mass of water (solvent) as shown below:

$m_{H_2O}=100g-38g=62g*\frac{1kg}{1000g}=0.062kg$

So compute the molality:

$m=\frac{n_{solute}}{m_{solvent}}=\frac{0.39mol}{0.062kg}=6.2m$

Regards.

7 0

4 years ago

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