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baherus [9]
3 years ago
5

A sample of ideal gas is in a sealed container. The pressure of the gas is 705 torr , and the temperature is 19 ∘C . If the temp

erature changes to 62 ∘C with no change in volume or amount of gas, what is the new pressure, P2, of the gas inside the container?
Chemistry
1 answer:
posledela3 years ago
8 0
808.77torr or 1.064atm
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What volume of a 2.25 M sodium chloride solution will contain 4.58 moles of sodium chloride
Rzqust [24]

Answer:

Option E. 2.04 L

Explanation:

Data obtained from the question include:

Molarity of NaCl = 2.25 M

Mole of NaCl = 4.58 moles

Volume =..?

Molarity is simply defined as the mole of solute per unit litre of the solution. It is represented mathematically as:

Molarity = mole /Volume

With the above formula, we can obtain the volume of the solution as follow:

Molarity = mole /Volume

2.25 = 4.58/volume

Cross multiply

2.25 x volume = 4.58

Divide both side by 2.25

Volume = 4.58/2.25

Volume = 2.04 L

Therefore, the volume of the solution is 2.04 L

6 0
3 years ago
How many atoms of each element are present in the compound
Lera25 [3.4K]
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8 0
3 years ago
Read 2 more answers
How many kilojoules (KJ) in 3.58 x 10^4 Calories?
Delicious77 [7]

Answer:

The answer to your question is: letter B

Explanation:

Data

3.58 x 10⁴ cal to joules

                                  1 calories ---------------  4.184 joules

                                   3.58 x 10⁴ cal-----------    x

                                   x = (  3.58 x 10⁴ x 4.184) / 1

                                   x = 149787.2 joules

                                  x = 1.5 x 10⁵    J

8 0
3 years ago
An iron(iii) sulfate hydrate is 18.4% water. What is the formula of the hydrate? What is the name of the hydrate?
aleksley [76]

Answer:- Formula of the hydrate is Fe_2(SO_4)_3.5H_2O and it's name is Iron(III)sulfate pentahydrate.

Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.

Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.

We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:

81.6gFe_2(SO_4)_3(\frac{1mol}{399.88g})

= 0.204molFe_2(SO_4)_3

18.4gH_2O(\frac{1mol}{18.02g})

= 1.02molH_2O

Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.

Fe_2(SO_4)_3=\frac{0.204}{0.204}  = 1

H_2O=\frac{1.02}{0.204} = 5

There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is Fe_2(SO_4)_3.5H_2O and the name of the hydrate is Iron(III)sulfate pentahydrate.


3 0
2 years ago
NH3 is nitrogen trihydride (ammonia) and BF3 is boron trifluoride. What is the name for AlCl3 and why?
Korvikt [17]
The answer is A. Aluminum Chloride it does not have the prefix "tri-" since it is ionic.
5 0
3 years ago
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