Answer:
The purpose of a filter paper inside a beaker is to retain the suspended solid particles found in the solution.
<em>The retention capacity of the filter paper will depend on the size of the pores of the filter</em>. Thus, for example, if the pores of the filter have a diameter of 1 mm, particles with a diameter greater than 1 mm will be retained, and the rest of the solution will pass through the pores.
The removal of impurities through filters is a physical separation process.
Answer:
T2 =21.52°C
Explanation:
Given data:
Specific heat capacity of sample = 1.1 J/g.°C
Mass of sample = 385 g
Initial temperature = 19.5°C
Heat absorbed = 885 J
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = Final temperature - initial temperature
885J = 385 g× 1.1 J/g.°C×(T2 - 19.5°C )
885 J = 423.5 J/°C× (T2 - 19.5°C )
885 J / 423.5 J/°C = (T2 - 19.5°C )
2.02°C = (T2 - 19.5°C )
T2 = 2.02°C + 19.5°C
T2 =21.52°C
Answer:
Na has the most similar configuration.
Explanation:
Na electron configuration: 1s²2s²2p⁶3s¹ or [Ne] 3s₁
Mg electron configuration: 1s²2s²2p⁶3s² or [Ne] 3s²
Be electron configuration: 1s²2s² or [He] 2s²
This is because Na and Mg are right next to each other in the same period (horizontal).
Answer : Option A) The body breaks down the molecules into molecules they need.
Explanation : Nutrient molecules are important because the body breaks the nutrient molecules and convert it into the absorb-able molecule that can generate energy for doing the activities of the body.
Nutrients are taken in the body in the form of carbohydrates which later on gets broken into glucose molecules and generates energy, proteins which is decomposed into amino acids, fats breaks down into fatty acids, minerals and salts are also nutrients which is essential nutrient for body.
Explanation:
1.undetectable to electromagnetic waves
2.hiding an object from an illumination containing diffre t wave lengths become difficult as the object sizes grow.
3. reduce the scattering by two orders.
