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AnnyKZ [126]
3 years ago
15

Many free radicals combine to form molecules that do not contain any unpaired electrons. The driving force for the radical–radic

al combination reaction is the formation of a new electron‑pair bond. Consider the chemical equation. N ( g ) + NO ( g ) ⟶ NNO ( g ) Write Lewis formulas for the reactant and product species in the chemical equation. Include nonbonding electrons.

Chemistry
1 answer:
Nataly [62]3 years ago
6 0

Answer:

The attached figure is the Lewis structure for the reaction.

Explanation:

The Lewis structure is a structure of the molecule in which valence electrons are represented as points that are located between the atoms that are linked, such that a pair of points means a simple covalent bond (line). The points representing non-bond electrons are placed adjacent to the atoms to which they are associated.

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What mass of C6H8O7 should be used every 7.0 X 10^2mg NaHCO3
Savatey [412]

Mass C₆H₈O₇ : 0.531484 g

<h3>Further explanation</h3>

Reaction

3NaHCO₃ (aq) + C₆H₈O₇ (aq) → 3 CO₂ (g) + 3 H₂O (l) + Na₃C₆H₅O₇ (aq)

MW NaHCO₃ : 84 g/mol

mass NaHCO₃ : 7.10² mg=0.7 g

mol NaHCO₃ :

\tt mol=\dfrac{0.7}{84}=0.0083

mol C₆H₈O₇ :

\tt \dfrac{1}{3}\times 0.0083=0.00277

MW C₆H₈O₇ : 192 g/mol

mass C₆H₈O₇ :

\tt mass=0.00277\times 192=0.53184

4 0
3 years ago
All objects have mass<br> O True<br> O False
ludmilkaskok [199]
The answerrrrr is truw
7 0
3 years ago
A certain intermolecular force is created due to a brief concentration of electrons between nonpolar molecules. What best explai
Paladinen [302]

Answer:

The correct answer is D

Explanation:

Many substances hold their molecules together in the liquid or solid bosom. This is due, in addition to the pressure and temperature conditions, by the forces of Van der Waals. These are still produced in nonpolar molecules by the movement of electrons through the molecules; in extremely short periods of time, their electrons "charge" towards one end of the molecule, producing small dipoles and keeping the molecules very close to each other.

8 0
3 years ago
Read 2 more answers
Consider the second-order reaction:
kirza4 [7]

Answer:

Initial concentration of HI is 5 mol/L.

The concentration of HI after 4.53\times 10^{10} s is 0.00345 mol/L.

Explanation:

2HI(g)\rightarrow H_2(g)+I_2(g)&#10;

Rate Law: k[HI]^2&#10;

Rate constant of the reaction = k = 6.4\times 10^{-9} L/mol s

Order of the reaction = 2

Initial rate of reaction = R=1.6\times 10^{-7} Mol/L s

Initial concentration of HI =[A_o]

1.6\times 10^{-7} mol/L s=(6.4\times 10^{-9} L/mol s)[HI]^2

[A_o]=5 mol/L

Final concentration of HI after t = [A]

t = 4.53\times 10^{10} s

Integrated rate law for second order kinetics is given by:

\frac{1}{[A]}=kt+\frac{1}{[A_o]}

\frac{1}{[A]}=6.4\times 10^{-9} L/mol s\times 4.53\times 10^{10} s+\frac{1}{[5 mol/L]}

[A]=0.00345 mol/L

The concentration of HI after 4.53\times 10^{10} s is 0.00345 mol/L.

5 0
4 years ago
Help with this please.
chubhunter [2.5K]

Answer:

a

Explanation:

cause its a tell me if you get it right hsnsnsjsjsjsnanajaksks bshsjjssjjsjddjhs h sshheggduejnd uhh cig jsjdufudneidisjsjjshhshshshhzhshjdhdudjsjdjdjdjdjdjdjsjsjsjsjsjsjdjdjsiiddudjdjdjsjdjjdjduxixuxixxuchucucufididididjdhxuueudhh see h bj too yxhxuxjdjsjsu

6 0
3 years ago
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