Many free radicals combine to form molecules that do not contain any unpaired electrons. The driving force for the radical–radic
al combination reaction is the formation of a new electron‑pair bond. Consider the chemical equation. N ( g ) + NO ( g ) ⟶ NNO ( g ) Write Lewis formulas for the reactant and product species in the chemical equation. Include nonbonding electrons.
1 answer:
Answer:
The attached figure is the Lewis structure for the reaction.
Explanation:
The Lewis structure is a structure of the molecule in which valence electrons are represented as points that are located between the atoms that are linked, such that a pair of points means a simple covalent bond (line). The points representing non-bond electrons are placed adjacent to the atoms to which they are associated.
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<u>Answer:</u> The mass defect for the formation of phosphorus-31 is 0.27399
<u>Explanation:</u>
Mass defect is defined as the difference in the mass of an isotope and its mass number.
The equation used to calculate mass defect follows:
where,
= number of protons
= mass of one proton
= number of neutrons
= mass of one neutron
M = mass number of element
We are given:
An isotope of phosphorus which is
Number of protons = atomic number = 15
Number of neutrons = Mass number - atomic number = 31 - 15 = 16
Mass of proton = 1.00728 amu
Mass of neutron = 1.00866 amu
Mass number of phosphorus = 30.973765 amu
Putting values in above equation, we get:
Hence, the mass defect for the formation of phosphorus-31 is 0.27399