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AnnyKZ [126]
3 years ago
15

Many free radicals combine to form molecules that do not contain any unpaired electrons. The driving force for the radical–radic

al combination reaction is the formation of a new electron‑pair bond. Consider the chemical equation. N ( g ) + NO ( g ) ⟶ NNO ( g ) Write Lewis formulas for the reactant and product species in the chemical equation. Include nonbonding electrons.

Chemistry
1 answer:
Nataly [62]3 years ago
6 0

Answer:

The attached figure is the Lewis structure for the reaction.

Explanation:

The Lewis structure is a structure of the molecule in which valence electrons are represented as points that are located between the atoms that are linked, such that a pair of points means a simple covalent bond (line). The points representing non-bond electrons are placed adjacent to the atoms to which they are associated.

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4 years ago
How many milliliters of 0.183 m hcl would be required to titrate 5.93 g koh?
jek_recluse [69]
  Molar mass:
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Number of moles of KOH :

5.93  / 36.5 => 0.1624 moles

<span>KOH + HCl = KCl + H₂O 
</span>
1 mole KOH --------------> 1 mole  HCl
0.1624 moles KOH ----> ?

moles HCl = 0.1624 x 1 / 1

= 0.1624 moles of HCl

V ( HCl ) = moles / molarity

V(HCl) = 0.1624 / 0.183

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3 0
3 years ago
How many moles of KClO3 must decompose in order to produce 9 moles of oxygen gas (O2) using the following reaction by completing
mezya [45]

<u>Answer:</u> 6 moles of KClO_3 will be decomposed.

<u>Explanation:</u>

We are given:

Moles of oxygen gas produced = 9 moles

The chemical equation for the decomposition of KClO_3 follows:

2KClO_3\rightarrow 2KCl+3O_2

By the stoichiometry of the reaction:

If 3 moles of oxygen gas is produced by 2 moles of KClO_3

So, 9 moles of oxygen gas will be produced by = \frac{2}{3}\times 9=6mol of KClO_3

Hence, 6 moles of KClO_3 will be decomposed.

4 0
3 years ago
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