1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
goldenfox [79]
3 years ago
5

A Geiger counter is used to measure

Chemistry
1 answer:
Fantom [35]3 years ago
7 0
It detects ionizing radiation<span> such as alpha particles, beta particles and gamma </span>rays<span>using the ionization effect produced in a </span>Geiger<span>–Müller tube; which gives its name to the instrument.</span>
You might be interested in
Red #40 has an acute oral LD50 of roughly 5000 mg dye/1 kg body weight. This means if you had a mass of 1 kg, ingesting 5000 mg
FrozenT [24]

Answer:

350 g dye

0.705 mol

2.9 × 10⁴ L

Explanation:

The lethal dose 50 (LD50) for the dye is 5000 mg dye/ 1 kg body weight. The amount of dye that would be needed to reach the LD50 of a 70 kg person is:

70 kg body weight × (5000 mg dye/ 1 kg body weight) = 3.5 × 10⁵ mg dye = 350 g dye

The molar mass of the dye is 496.42 g/mol. The moles represented by 350 g are:

350 g × (1 mol / 496.42 g) = 0.705 mol

The concentration of Red #40 dye in a sports drink is around 12 mg/L. The volume of drink required to achieve this mass of the dye is:

3.5 × 10⁵ mg × (1 L / 12 mg) = 2.9 × 10⁴ L

8 0
3 years ago
In the absence of sodium methoxide, the same alkyl bromide gives a different product. Draw an arrowpushing mechanism to account
hoa [83]

Answer:

See explanation below

Explanation:

The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.

Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.

For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)

For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.

3 0
3 years ago
In need of help very soon please.
NemiM [27]

Answer:

hello, i hope this helps.

Explanation:

1 - group

2 - period

3 - periodic table

4 - family

5 - octet rule

6 - valence electrons

6 0
2 years ago
Chemical changes<br> involve the breaking and making of chemical bonds.<br><br> The answer is always
larisa [96]

Answer:

Chemical reactions involve breaking chemical bonds between reactant molecules (particles) and forming new bonds between atoms in product particles (molecules). The number of atoms before and after the chemical change is the same but the number of molecules will change.

Explanation:

6 0
2 years ago
What is the freezing point of a solution of 0.5 mol of LiBr in 500 mL of water? (Kf = 1.86°C/m) –1.86°C –7.44°C –5.58°C –3.72°C
tresset_1 [31]

Answer:

  • Last choice: <em><u>- 3.72°C</u></em>

Explanation:

The freezing point depression in a solvent is a colligative property: it depends on the number of solute particles.

The equation to predict the freezing point depression in a solvent is:

  • ΔTf = Kf × m × i

Where,

  • ΔTf is the freezing point depression of the solvent,
  • m is the molality,
  • Kf is the cryoscopic molal constant of the solvent, and i is the Van'f Hoff factor, which is the number of ions produced by each unit formula of the ionic compound.

The calcualtions are in the attached pdf file. Please, open it by clicking on the image of the file.

Download pdf
6 0
2 years ago
Other questions:
  • What effect does thermal energy have on the rate of chemical reactions?
    8·2 answers
  • Suppose a large atom bonds with a small
    11·1 answer
  • Electroplating is a method of rust prevension
    6·1 answer
  • Envirnmental pollution caused by production of iron
    8·1 answer
  • What is the name for the prevailing global wind pattern that comes from the poles and blows from east to west?
    15·1 answer
  • Conclusion on friendship​
    11·2 answers
  • Which of the following remains would be most likely only be found as a compression fossil?
    14·2 answers
  • What conditions are needed to prevent iron from rusting?​
    11·1 answer
  • Which species do you think is best adapted to a diet of large, tough-to-crack<br> seeds? Explain.
    14·2 answers
  • For the balanced equation shown below, if the reaction of 34.6 grams of C2H4F2 produces 6.90 grams of H2O, what is the percent y
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!