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Vika [28.1K]
3 years ago
6

Which of the following is the best hypothesis?

Chemistry
1 answer:
torisob [31]3 years ago
8 0

Answer:

b

Explanation:

i think it is b

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6. dissolving ice tea mix in water
Cloud [144]

Answer:

Dissolving ice tea mix in water is a chemical change

Explanation:

It is a chemical change because you can not bring back the ice tea mix back if you mix it in water.

Hope it helps

6 0
3 years ago
A pressure cooker contains 5.68 liters of air at a temperature of 394 K. If the absolute pressure of the air in the pressure coo
Arturiano [62]

Answer:

Explanation:

We shall find out volume of air at NTP or at 273 K and 10⁵ Pa ( 1 atm )

Let it be V₂

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

\frac{2\times 10^5\times 5.68}{394} =\frac{10^5\times V_2}{273}

V₂ = 7.87 litres

22.4 litres of any gas is equivalent to 1 mole

7.87 litres of air will be equivalent to

7.87 / 22.4 moles

= .35 moles .

7 0
3 years ago
Strategies for Preve.
Veseljchak [2.6K]

Answer:

i don't know myself either

3 0
3 years ago
Write balanced complete ionic equation for MgS(aq)+CuCl2(aq) = CuS(s)+MgCl2(aq)
oee [108]
<span>The balanced chemical ionic equarion of MgS(aq)+CuCl2(aq) = CuS(s)+MgCl2(aq) would be as follows:

</span><span>Mg2+ + S2- + Cu 2+ + 2 Cl- ==> CuS + Mg2+ + 2 Cl-

Therefore, the net equation would be:

</span><span>Cu 2+ + S 2-  ===> CuS 
</span><span>
Hope this helps.


</span>
8 0
3 years ago
Read 2 more answers
2.00 g of an unknown gas at STP fills a 500. mL flask. What is the molar mass of the gas?
otez555 [7]

Answer:

100g/mol

Explanation:

Given parameters:

Mass of unknown gas  = 2g

Volume of gas in flask  = 500mL  = 0.5dm³

Unknown:

Molar mass of gas = ?

Solution:

Since we know the gas is at STP;  

        1 mole of substance occupies 22.4dm³ of space at STP

    Therefore,

            0.5dm³ will have  0.02mole at STP

                     

Now;

   Number of moles  = \frac{mass}{molar mass}  

      Molar mass  = \frac{mass}{number of moles}   = \frac{2}{0.02}   = 100g/mol

4 0
3 years ago
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