If an electron absorbs enough energy it would jump to a higher energy level.
Answer: Provided in the explanation section
Explanation:
Our questions says that:
It is usually assumed that an action potential begins immediately at the cathode. If this were true, both methods for calculating conduction velocity would provide the same answer. However, when a strong stimulus intensity is used, the action potential may begin some distance away from the cathode. Under these conditions, the difference method would be more accurate.Did you observe any important difference between the conduction velocity values?
Answer to this :
By using the difference method, you subtract out any "uncertainties" involved in the measurement of latencies. Say for example, saw we are uncertain as to where the AP's are actually originating within the vicinity of the stimulating electrodes, this "error" will be introduced into both latency measurements, and therefore subtracted out when performing a difference method calculation.
However, the difference method is only experimentally sound when one is dealing with the same population of nerve fibres over the recording electrodes used, which is not the case with the sciatic nerve, as it is a short nerve, and thin at one end.
The non-uniformity of the nerve, and the difficulty in making accurate measurements of very small distances and latencies are principal points to consider when making conduction velocity measurements. Naturally if the nerve studied were longer and more uniform, we would improve the accuracy of our calculations.
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I believe the first one is correct.
Answer:
l = 0, 1, and 2; it is in a d orbital.
Explanation:
1. Angular momentum quantum number
One square means l = 0.
Three squares mean l = 1.
Five squares mean l = 2.
If an atom contains electrons with l = 2, it must also have electrons with l = 0 and 1.
Thus, the electrons in the atom can be assigned the angular momentum quantum numbers l = 0, 1, and 2.
Those in a set of five squares all have l = 2.
2. Location of electron
The last electron is the lone electron in the fifth square. Since l = 2, the electron is in a d orbital.
1) Balanced chemical reaction
H2SO4 (aq) + 2NaOH(aq) ----> Na2SO4(aq) + 2 H2O(liq)
2) Molar ratios
1 mol H2SO4 : 2 mol NaOH : 1 mol Na2SO4
3) Number of moles of NaOH
M = n / V => n = M * V = 1.0 M * 0.018 liter = 0.018 mol
of NaOH.
4) Determine the number of moles of H2SO4 using proportionality
1 mol H2SO4 / 2 mol NaOH = x / 0.018 mol NaOH
Solve for x:
x = 0.018 mol NaOH * 1 mol H2SO4 / 2 mol NaOH =0.009 mol H2SO4
5) Calculate the molarity using 0.009 mol and 25 mililiters
M = n / V = 0.009 mol / 0.025 liter = 0.36 M
Answer: the concentration of the H2SO4 is 0.36 M
