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3 years ago

As air becomes warmer, it

Physics

2 answers:

shutvik [7]3 years ago

3 0

As air becomes warmer it condensates

skelet666 [1.2K]3 years ago

3 0

As air becomes warmer, it "compressed"

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What happens to the gravitational attraction between 2 objects

amm1812

Answer:

It decreases.

Explanation:

between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases

7 0

2 years ago

Put on the ground a shrimp that has just been taken out of water.Now touch the shrimp from a distance by a stick.The shrimp will

Assoli18 [71]

Answer: Yes.

Explanation:

8 0

2 years ago

Carbon dioxide (CO2) gas in a piston-cylinder assembly undergoes three processes in series that begin and end at the same state

topjm [15]

Answer:

a) W =400 kJ

b) W = 0 kJ

c) W =-160.944 KJ

Explanation:

Given

Process 1 ---> 2

The relation of the process P = constant

Pressure of point (1) P1 = 10 bar = P2

Volume of point (1) V1 = 1 m^3

Volume of point (2) V2 =4 m^3

The relation of the process V = constant

Process 2 ---> 3

The relation of the process V = constant

V3 = V2

Pressure of point (3) P3 = 10 bar

Volume of point (3) V3 = 4 m^3

Process 3 ---> 1 

The relation of the process PV = constant

Required

Sketch the processes on the PV coordinates

The work for each process in kJ

Solution

The work is defined by

W= $\int\limits^a_b {x} \, dx$

a=V2

b=V1

x=P

dx=dV

Process 1 ---> 2

P3 = P4 = 5 bar

W= $\int\limits^a_b {x} \, dx$

a=V3

b=V2

x=4

dx=dV

putting the value of a, b, x, dx in above integral

W=400 kJ

Process 2 ---> 3 

V = constant Then there is no change in the volume,hence W = 0 kJ

Process 3 ---> 1

By substituting with point (1) --> 5 x .2 = C ---> C = 1 P = 5V^-1

W= $\int\limits^a_b {x} \, dx$

a=V1

b=V3

x=1V^-1

dx=dV

putting the value of a, b, x, dx in above integral

W=| ln V | limit a and b

= -160.944 KJ

5 0

3 years ago

Find the west component of 45 m 19º S of W

BaLLatris [955]

Answer:

The west component of the given vector is - 42.548 meters.

Explanation:

We need to translate the sentence into a vectoral expression in rectangular form, which is defined as:

$(x, y) = (r_{x}, r_{y})$

Where:

$r_{x}$ - Horizontal component of vector distance, measured in meters.

$r_{y}$ - Vertical component of vector distance, measured in meters.

Let suppose that east and north have positive signs, then we get the following expression:

$(x, y) = (-45\cdot \cos 19^{\circ}, -45\cdot \sin 19^{\circ})\,[m]$

$(x, y) = (-42.548,-14.651)\,[m]$

The west component corresponds to the first component of the ordered pair. That is to say:

$x = -42.548\,m$

The west component of the given vector is - 42.548 meters.

8 0

3 years ago

The altitude of a hang glider is increasing at a rate of 6.75 m/s. At the same time, the shadow of the glider moves along the gr

Rufina [12.5K]

Answer:

16.45 m/s

Explanation:

Let y be the vertical distance and x be the horizontal distance

We are given that

The altitude of hang glider increasing at the rate= $v_y=\frac{dy}{dt}==6.75m/s$

The shadow of the glider moves along the ground at speed= $v_x=\frac{dx}{dt}=15m/s$

We have to find the magnitude of glider's velocity.

We know that

Magnitude of velocity= $v=\sqrt{v^2_x+v^2_y}$

Substitute the values

$v=\sqrt{(15)^2+(6.75)^2}$

$v=\sqrt{225+45.5625}$

$v=16.45m/s$

Hence, the magnitude of glider's velocity=16.45 m/s

4 0

3 years ago