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4 years ago

Describe how all the air in the oven becomes hot?

Physics

1 answer:

vladimir1956 [14]4 years ago

4 0

I think through convection I forget. Plus its enclosed (and, well closed)

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A plane is flying due west at 34 m/s. It encounters a wind blowing at 19 m/s south. Find the resultant veloci

Drupady [299]

Answer:

<em>The resultant velocity has a magnitude of 38.95 m/s</em>

Explanation:

<u>Vector Addition</u>

Given two vectors defined as:

$\vec v_1=(x_1,y_1)$

$\vec v_2=(x_2,y_2)$

The sum of the vectors is:

$\vec v=(x_1+x_2,y_1+y_2)$

The magnitude of a vector can be calculated by

$d=\sqrt{x^2+y^2}$

Where x and y are the rectangular components of the vector.

We have a plane flying due west at 34 m/s. Its velocity vector is:

$\vec v_1=(-34,0)$

The wind blows at 19 m/s south, thus:

$\vec v_2=(0,-19)$

The sum of both velocities gives the resultant velocity:

$\vec v =(-34,-19)$

The magnitude of this velocity is:

$d=\sqrt{(-34)^2+(-19)^2}$

$d=\sqrt{1156+361}=\sqrt{1517}$

d = 38.95 m/s

The resultant velocity has a magnitude of 38.95 m/s

3 0

3 years ago

A thin, rectangular sheet of metal has mass M and sides of length a and b. Find the moment of inertia of this sheet about an axi

Lubov Fominskaja [6]

Answer:

The moment of inertia is $I=\frac{M}{12} a^{2}$

Explanation:

The moment of inertia is equal:

$I=\int\limits^a_b {r^{2} } \, dm$

If r is $-\frac{a}{2}$

and $dm=\frac{M}{a} dr$

$I=\int\limits^a_b {r^{2}\frac{M}{a} } \, dr\\a=\frac{a}{2} \\b=-\frac{a}{2}$

$I=\frac{M}{a} \int\limits^a_b {r^{2} } \, dr\\\\I=\frac{M}{a} (\frac{M}{3} )_{b}^{a}\\ I=\frac{M}{3a} (\frac{a^{3} }{8} +\frac{a^{3} }{8} )\\I=\frac{M}{12} a^{2}$

7 0

4 years ago

Suzanne makes a tower out of six identical plastic box. Then she uses a pan balance to measure the mass of the tower. She finds

EleoNora [17]

Take the 72 g and divid it by 6 which would equal 12 g each

5 0

3 years ago

Read 2 more answers

How many types of protenies are there in all life as we know it

Sever21 [200]

let me know!! i need the same answer,

8 0

3 years ago

You pull with a force of 295 N on a rope that is attached to a block of mass 22 kg, and the block slides across the floor at a c

Sergeeva-Olga [200]

Answer:

Fnet = 0

Explanation:

Since the block slides across the floor at constant speed, this means that it's not accelerated.
According Newton's 2nd Law, if the acceleration is zero, the net force on the sliding mass must be zero.
This means that there must be a friction force opposing to the horizontal component of the applied force, equal in magnitude to it:

$F_{appx} = F_{app} * cos \theta = 295 N * cos 35 = 242 N (1)$

In the vertical direction, the block is not accelerated either, so the sum of the normal force and the vertical component of the applied force, must be equal in magnitude to the force of gravity on the block:

$F_{appy} = F_{app} * cos \theta = 295 N * sin 35 = 169 N (2)$

⇒ 169 N + Fn = Fg = 216 N (3)

This means that there must be a normal force equal to the difference between Fappy and Fg, as follows:
Fn = 216 N - 169 N = 47 N (4)

6 0

3 years ago