The interaction between two like-charged objects is repulsive. ... Positively charged objects and neutral objects attract each other; and negatively charged objects and neutral objects attract each other.
To solve this problem, we must remember about the law of
conservation of momentum. The initial momentum mist be equal to the final
momentum, that is:
m1 v1 + m2 v2 = (m1 + m2) v’
where v’ is the speed of impact
Since we are not given the masses of each car m1 and m2,
so let us assume that they are equal, such that:
m1 = m2 = m
Which makes the equation:
m v1 + m v2 = (2 m) v’
Cancelling m and substituting the v values:
50 + 48 = 2 v’
2 v’ = 98
v ‘ = 49 km/h
<span>The speed of impact is 49 km/h.</span>
Answer:I would guess a plane
Assuming they all Thad the same velocity....
Answer:
B. Kinetic energy.............
Answer:
The magnitude of induced emf is 5.4 V
Explanation:
Given:
Magnetic field 
T
Area of loop 
Time take to reduce loop to zero 
sec
To find induced emf we use faraday's law,
Induced emf is given by,
Here minus sign shows lenz law, for finding magnitude of emf we ignore it.
Where 
Put the value of flux and find induced emf,
V
Therefore, the magnitude of induced emf is 5.4 V
