Answer:

Explanation:
<h3><u>Given data:</u></h3>
Acceleration = a = 3 m/s²
Force = F = 150 N
<h3><u>Required:</u></h3>
Mass = m = ?
<h3><u>Formula:</u></h3>
F = ma
<h3><u>Solution:</u></h3>
Put the givens in the formula
150 = m (3)
Divide 3 to both sides
150/3 = m
50 kg = m
m = 50 kg
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Natural Frequency
Hope that helped!
Answer:
45.89m/s²
Explanation:
Given
Distance S = 305m
Time t = 3.64s
To get the acceleration during this run, we will apply the equation of motion:
S = ut+1/2at²
Substitute the given parameters into the formula and calculate the value of a
305 = 0+1/2 a(3.64)²
304 = 1/2(13.2496)a
304 = 6.6248a
a = 304/6.6248
a = 45.89m/s²
Hence the average acceleration during this run is 45.89m/s²
Answer:
<em>The end of the ramp is 38.416 m high</em>
Explanation:
<u>Horizontal Motion
</u>
When an object is thrown horizontally with an initial speed v and from a height h, it follows a curved path ruled by gravity.
The maximum horizontal distance traveled by the object can be calculated as follows:

If the maximum horizontal distance is known, we can solve the above equation for h:

The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:


h= 38.416 m
The end of the ramp is 38.416 m high