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3 years ago

Describe electric potential energy

1 answer:

3 0

Is potential energy that results from conservative Coulomb forces and is associated with the configuration of a particular set of point charges within a defined system

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A 600-kg car accelerates from rest to 10 m/s^2. What is the force on the car?

iris [78.8K]

Answer:

60000 newtons

Explanation:

Force=mass × acceleration

60000

3 0

3 years ago

A succession of single tones or pitches perceived as a unit is called:

jeka57 [31]

A succession of single tones or pitches perceived as a unit is called a melody. It is a linear succesion of tones in music that is seen as one single entity. It is a combination of rhythm, pitch and tonal color. Melodies usually has one ormore motifs or phrases that are being repeated all throughout a composition. Melodies are characterized by the melodic motion it posses , the pitch, intervals between the pitches, continuity and pitch range. Due to the a wide range of melodies that can be made from tones, differet genres of music arise. Examples are Jazz, Rock music, Classical, pop, R&B and the like.

5 0

3 years ago

starting at a position of 0 m, if the man is moving at a constant velocity of 2 m/s, it will take seconds for him to reach a pos

Harman [31]

The calculated time is 6 seconds.

Time is defined by physicists as the flow of events from the past through the present and into the future. In essence, a system is timeless if it is unchanging. When describing events that take place in three-dimensional space, time can be thought of as the fourth dimension of reality. Even if time isn't directly connected to energy, it is undoubtedly connected to many other components of energy. For instance, the movement of energy across the universe can affect the direction of time (from the past to the future).

V= 2 m/s

d=12 m

t=?

we know that velocity=displacement / time

time= displacement / velocity

= 12/2

=6 seconds

the calculated time is 6 seconds.

Learn more about time here-

brainly.com/question/28050940

#SPJ4

4 0

1 year ago

Gold is the most ductile of all metals. For example, one gram of gold can be drawn into a wire 2.05 km long. The density of gold

arsen [322]

Answer:

Resistance of gold wire, $R=1977 \times 10^3 ohm$

Explanation:

In this question we have given

Density of gold, $d=19.3\times 10^3 \frac{kg}{m^3}$

resistivity of gold, $r=2.44\times 10^{-8} ohm.m$

Length of wire, $L= 2.05 km$

Temperature, $T= 20^oC$

We know that relation between volume and density is given as

$Density= \frac{mass}{Volume}$

Therefore, volume occupied by one gram gold is given as,

$V=\frac{.001 kg}{19.3\times 10^3 Kg m^{-3}} = 5.181\times 10^{-8} m^3$ .........(1)

We Know that Volume of gold wire which is cylindrical in shape is given by following formula

$V=\pi \times r^2 \times L$ ......(2)

Here,

$A= \pi \times r^2$ ...........(3)

here A is the cross sectional area of cylendrical gold wire

From equation 2 and 3

we got

$V=A \times L$ ...............(4)

on comparing equation 1 and equation 4, we got,

$A \times L=5.181\times 10^{-8} m^3$

$A=\frac{5.181\times 10^{-8} m^3}{2050 m}$

$A=2.53\times 10^{-11}m^2$

we know that resistance and resistivity are related by following formula,

$Resistance = resistivity\times \frac{L}{A}$ ................(5)

Put values of resistivity, A and L in equation 5, we got

$R = \frac{2.44 \times 10^{-8} ohm.m \times 2050 m}{2.53\times 10^{-11} m^2}$

$R=1977 \times 10^3 ohm$

Therefore resistance of gold wire, $R=1977 \times 10^3 ohm$

7 0

3 years ago

A 5 kg projectile is fired at an angle of 25o above the horizontal. Its initial velocity is 200 m/s and just before it hits the

lina2011 [118]

Answer:

The change in the mechanical energy of the projectile is 43,750 J

Explanation:

Given;

mass of the projectile, m = 5 kg

initial velocity of the projectile, u = 200 m/s

final velocity of the projectile, v = 150 m/s

The change in mechanical energy is calculated from the principle of conservation of energy;

ΔP.E = ΔK.E

The change in potential energy is zero (0)

0 = ΔK.E

ΔK.E = K.E₁ - K.E₂

ΔK.E = ¹/₂mu² - ¹/₂mv²

ΔK.E = ¹/₂m(u² - v²)

ΔK.E = ¹/₂ x 5(200² - 150²)

ΔK.E = 43,750 J

Therefore, the change in the mechanical energy of the projectile is 43,750 J

4 0

3 years ago